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A measure of the quantity of matter is<br> a. density.<br> c. force.<br> b. weight.<br> d. mass.

ohaa [14]

A measure of the quantity of matter is called mass. D.

This is how much of matter is contained in an object. It is different from weight, which is the pull of gravity on an object.

6 0

4 years ago

a block with a mass of 3 kg is swung on a cord in a horizontal circle with a radius of 2m. the speed of the block is 6m/s^. the

Ivenika [448]

Given Information:

Mass = m = 3 kg

Speed = v = 6 m/s

Radius = r = 2 m

Required Information:

Magnitude of the acceleration = a = ?

Answer:

Magnitude of the acceleration = 18 m/s²

Explanation:

The acceleration of the block traveling along a circular path with some velocity is given by

a = v²/r

a = 6²/2

a = 36/2

a = 18 m/s²

Therefore, the magnitude of the acceleration of the block is most nearly equal to 18 m/s².

Bonus:

The corresponding force acting on the block can be found using

F = ma (a = v²/r)

F = mv²/r

7 0

3 years ago

Read 2 more answers

Identify the labeled parts in the figure.

ad-work [718]

Answer:

Chemical symbols Al, O, H, O or a,c,f,h.

Coefficient 2 or e.

Number of atoms of the element - b,d ,g.

One atom of the element - i.

5 0

3 years ago

Two cars have identical horns, each emitting a frequency of fs = 406 Hz. One of the cars is moving with a speed of 10.5 m/s towa

Archy [21]

Answer:

$f_{B}=12.8 Hz$

Explanation:

Let's start finding the frequency heard by the bystander due to the moving car. We need to use Doppler effect here:

$f_{obs}=f_{s}\left(\frac{v}{v-v_{car}}\right)$

v is the speed of sound (v = 343 m/s)

So, we have:

$f_{obs}=406\left(\frac{343}{343-10.5}\right)=418.8 Hz$

Now, the beat frequency heard by the bystander is the combine of the frequencies, it means the difference between them. Therefore the equation is given by:

$f_{B}=f_{obs}-f_{s}=418.8-406=12.8 Hz$