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3 years ago

What is Martyn’s job?

Physics

1 answer:

ikadub [295]3 years ago

8 0

Teacher ‍ yesss bc i saw

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A car accelerates uniformly from rest and reaches a speed of 22.5 m/s in 8.96 s. Assume the diameter of a tire is 58.9 cm. (a) F

Murljashka [212]

Answer:

54.4747649021

38.2003395586 rad/s

Explanation:

Acceleration

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{22.5-0}{8.96}\\\Rightarrow a=2.51116071429\ m/s^2$

Distance covered

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 2.51116071429\times 8.96^2\\\Rightarrow s=100.8\ m$

Number of revolutions

$n=\dfrac{s}{\pi d}\\\Rightarrow n=\dfrac{100.8}{\pi 0.589}\\\Rightarrow n=54.4747649021$

Number of revolutions is 54.4747649021

Angular speed is given by

$\omega=\dfrac{v}{r}\\\Rightarrow \omega=\dfrac{22.5}{0.589}\\\Rightarrow \omega=38.2003395586\ rad/s$

The final angular speed is 38.2003395586 rad/s

8 0

4 years ago

By how many degrees fahrenheit can the temperature of one metric ton of water be raised with the addition of 110 thousand btus o

Svetllana [295]

1 BTU mean 1 degree of F increased for 1 pound mass. Since the mass unit is in kg that means you need to convert it into pound. One metric ton means 1000kg and 1 kg mean 2.20462lb, then the water mass is: 1000kg x 2.20462lb/kg= 2204.62lb.

You are putting 110,000 btus of heat, so the calculation would be

Temperature increase= energy/mass = 110000btus/ 2204.62lb= 49.9 degree

5 0

4 years ago

Joshua skates in a straight line at a constant speed for 1 min, then begins going in circles at the same rate of speed, and fina

AlexFokin [52]

Answer:

When he begins going in circles at the same rate of speed

Explanation

When he begins going circles he speed begins to increase means he is accelerating

7 0

3 years ago

i like honey but when u put it on your feet it sticks to the ground. how do i avoid the stickyness of honey when i want to clean

Gre4nikov [31]

Answer:

please stop asking questions

Explanation:

6 0

3 years ago

Read 2 more answers

A person takes a trip, driving with a constant

podryga [215]

For this problem, we are asked to calculate for the distance traveled. We set up the equations as follows:
Distance = 61 km/hr * (time + 20.8/60 s) Distance = 98.5 km/hr * time

We equate the two equations, then we can solve for the time spent on the trip. Hope this answers the question. Have a nice day.

8 0

3 years ago