<u>Answer-</u>
<em>The interval where the function is diffrentiable is </em>
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
<u>Solution-</u>
The given expression is,

The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.
The function continuous everywhere except at x = 1, because

at x = 1, its limit does not exist.
Therefore, apart from x=1, this function is differentiable everywhere. The interval will be
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
Answer:
It is:
86387.13241
Step-by-step explanation:
We are considering the function

the graph of this function is the graph of the parent function

after applying the following steps.
1. multiply by -1:

is

reflected with respect to the x-axis.
2. multiply by 5:

is

shrinked towards the y axis.
for example, consider x=1/2

now this means that

is "lower" than

, which means there is a shrinking of the graph.
3. add 5:

is

shifted 5 units up.
4.
so the graph of the function a) opens down, b) is shifted 5 units up, c) is not wider than the parent function
Answer: False
Answer:
I THINK a=3 b=9
Step-by-step explanation: