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Nesterboy [21]
3 years ago
13

What is the median of 7, 9, 6, 15, 22, 25, 31? 15 16 19 24

Mathematics
1 answer:
mash [69]3 years ago
3 0

Answer:

15

Step-by-step explanation: you basically write it down in numerical order or 1 2 3 4 5 6 7 8 9 10 etc. then if it is an odd number then you choose the one that has an equal amount on each side left and right. if it is even then you need to do the same thing but find two numbers that are side by side and have an equal amount on both sides.

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Hello Brainly pleas help
gtnhenbr [62]

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can you take a better pick

Step-by-step explanation:

8 0
3 years ago
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Find x using completing the square method<br> x^2+16n+28 = 0
Nezavi [6.7K]

Answer:

x=√−16n−28 or x=−√−16n−28

Step-by-step explanation:

Step 1: Add -16n to both sides.

x2+16n+28+−16n=0+−16n

x2+28=−16n

Step 2: Add -28 to both sides.

x2+28+−28=−16n+−28

x2=−16n−28

Step 3: Take square root.

x=√−16n−28 or x=−√−16n−28

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3 years ago
What is the relationship between gross pay and net pay? A. Gross pay is less than net pay B. Gross pay is more than net pay C. G
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Answer:b

Step-by-step explanation:

7 0
2 years ago
How many centimeters are in 1 mile
kvasek [131]

Answer:

1 mile = 160934 cm

Step-by-step explanation:

1 mile = 1609.34 m

1 m = 100 cm

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3 0
3 years ago
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Petes boat can travel 48 miles upstream in 4 hours. The return trip takes 3 hours. Find the speed of the boat in still water and
tankabanditka [31]
So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up

going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r

notice, the distance is the same, upstream as well as downstream
thus   \bf \begin{cases}&#10;b=\textit{rate of the boat}\\&#10;r=\textit{rate of the river}&#10;\end{cases}\qquad thus&#10;\\\\\\&#10;&#10;\begin{array}{lccclll}&#10;&distance&rate&time(hrs)\\&#10;&----&----&----\\&#10;upstream&48&b-r&4\\&#10;downstream&48&b+4&3&#10;\end{array}&#10;\\\\\\&#10;&#10;\begin{cases}&#10;48=(b-r)(4)\to 48=4b-4r\\\\&#10;\frac{48-4b}{-4}=r\\&#10;--------------\\&#10;48=(b+r)(3)\\&#10;-----------------------------\\\\&#10;thus\\\\&#10;48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)&#10;\end{cases}

solve for "r", to see what the stream's rate is

what about the boat's? well, just plug the value for "r" on either equation and solve for "b"
5 0
3 years ago
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