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Alisiya [41]
4 years ago
13

4n-2/10=7/5 What do I do

Mathematics
1 answer:
Misha Larkins [42]4 years ago
8 0
Then simplify and you should have 2/5

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Lenny's car is worth $18,000 after 5 years. When the car was new, it sold for $24,000. What is the depreciation rate?
Tatiana [17]
If you doing straight-line depreciation rate

(P-s)÷N

(24000-18000)/5=1200

where p is cost, s is sold or salvage value, N is number of years
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Which is equivalent to 64 1/4? A. 2(4 square root 4) B. 4 C. 16 D. 16 4 square root 4 (Look at image please)​
Nimfa-mama [501]

Answer:

The answer is A

Step-by-step explanation:

64¼ = (2⁶)^¼ so 2^⅔.

3 0
3 years ago
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Help out please !!!!
valentinak56 [21]

Answer:

B maybe

Step-by-step explanation:

8 0
3 years ago
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32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t
garri49 [273]

Answer:

a. \ 0.2107\\\\b.\ 0.6727\\\\c.\ 0.8157

Step-by-step explanation:

a. Our random variable follows a binomial distribution which is defined as:

P(X=x)={n \choose x } \times p^x \times (1-p)^n^-^x where p is the probability of success, n the sample size and x the random variable.

-Given that p=0.32, n=10 what's P(X=2):

P(X=2)={10\choose 2}\times 0.32^2 \times (1-0.32)^8\\=0.2107

Hence, the probability of exactly two is 0.2107

b. The probability that more than two adults are more likely to make purchases during a sales tax holiday is given by:

P(X>2)=1-P(X=0)-P(X=1)-P(X=2)\\=1-{10\choose 2}\times 0.32^2 \times (1-0.32)^8-{10\choose 1}\times 0.32^1 \times (1-0.32)^9-{10\choose 0}\times 0.32^0 \times (1-0.32)^1^0\\=1-0.2107-0.0995-0.0211\\=0.6727

Hence the probability of more that two adult purchases is 0.6727

c. The probability that the number of adults who say they are more likely to make purchases between 2 and 5 is obtain by summing the the probabilities

p(x=2)+p(x=3)+p(x=4)+p(x=5).

-From b above, we already have p(x=2)=0.2107. Therefore:

P(2\leq X\leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\\=0.2107+{10\choose 3}\times 0.32^3 \times (1-0.32)^7+{10\choose 4}\times 0.32^4 \times (1-0.32)^6+{10\choose 5}\times 0.32^5 \times (1-0.32)^5\\=0.2107+0.2644+0.2177+0.1229\\=0.8157

-Hence the probability of between two and five is 0.8157

7 0
3 years ago
25 Points!!!!
o-na [289]
You can prove that angle C is 30°. This is because we know that angle B is 120° also, and cointerior angles add to 180°, which makes angle BCF 60°. Then we can divide this by 2 as angle BCF is bisected by AC, so therefore angle ACF is 30° as 60 ÷ 2 = 30.

You can then prove angle A is 90°. First we can find angle BAC because it is part of a triangle, and angles in a triangle add to 180°. This means we can do 30 + 120 = 150, and 180 - 150 = 30° which is angle BAC. Then we do 120 - 30 = 90, as the whole of angle BAF is 120°.

I hope this helps!
3 0
4 years ago
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