(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
The answer is 126.56 really hope that’s right:)
Answer:
The roots of equations are as m =
And n =
Step-by-step explanation:
The given quadratic equation is 2 x² + 6 x - 1 = 0
This equation is in form of a x² + b x + c = 0
Let the roots of the equation are ( m , n )
Now , sum of roots = 
And products of roots = 
So, m + n =
= - 3
And m × n = 
Or, (m - n)² = (m + n)² - 4mn
Or, (m - n)² = (-3)² - 4 (
)
Or, (m - n)² = 9 + 2 = 11
I.e m - n = 
Again m + n = - 3 And m - n = 
Solving this two equation
(m + n) + ( m - n) = - 3 + 
I.e 2 m = - 3 + 
Or, m = 
Similarly n =
Hence the roots of equations are as m =
And n =
Answer
Answer:
Look below for coordinates
Step-by-step explanation:
A: -2, 3 to A': -2, -3
B: 5, -2 to B': 5, 2
C: -5, 1 to C': -5, -1
Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)
Answer:
The first five terms are;
-3,-7,11,-29,69
Step-by-step explanation:
The recursive definition of the sequence is
,
and
.
When n=3, we obtain;
.
.
.
.
When n=4
.
.
When n=5
.
.
Therefore the first five terms are;
-3,-7,11,-29,69