Answer:
Well, it's the perimeter, so...40.
You just calculate the perimeter of a rectangle with the lenght of 12 and width of 8, by the formula
or you can factor it out.
Find the value of the variable such that the value of 5−a is 20 greater than the value of 6a−1
1 answer:
<h3>Answer:</h3>
a = -2
<h3>Explanation:</h3>We want (5-a) to be 20 more than (6a-1). Then we can write ...
... (5-a) = (6a-1) +20
If we add (a-19) to both sides, we get
... -14 = 7a
... -2 = a . . . . . divide by 7
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<em>Comment on the graph</em>
In the attached, we use the variable x, because this graphing calculator likes variables named x and y. We graph each expression and find the place where they both have the same value for the same value of x (the point of intersection). The value of the variable x at that point is -2, the solution we seek.
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Answer:
The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.
Step-by-step explanation:
Consider the provided information.
It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.
The probability of winning is 1/38. So, the probability of loss is 37/38.
Now, find the expected value of the game to the player as shown:
Hence, the expected value of the game to the player is -$0.2105.
Now find the expect to loss if played the game 1000 times.
1000×(-$0.2105)=-$210.5
Therefore, the expected loss if played the game 1000 times is -$210.5.