Find the value of the variable such that the value of 5−a is 20 greater than the value of 6a−1
1 answer:
<h3>Answer:</h3>
a = -2
<h3>Explanation:</h3>We want (5-a) to be 20 more than (6a-1). Then we can write ...
... (5-a) = (6a-1) +20
If we add (a-19) to both sides, we get
... -14 = 7a
... -2 = a . . . . . divide by 7
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<em>Comment on the graph</em>
In the attached, we use the variable x, because this graphing calculator likes variables named x and y. We graph each expression and find the place where they both have the same value for the same value of x (the point of intersection). The value of the variable x at that point is -2, the solution we seek.
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