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3 years ago

Secret Decimal Number Riddle I have 2 ones 22 hundredths 12 tenths What number am I?

Mathematics

1 answer:

Ann [662]3 years ago

6 0

3.22 is the correct answer

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Plssss help (the answer choices are the same for all)

Lilit [14]

1) x < 8/3
2) x > -9
3) Infinite Solutions
4) No Solution

Please correct me if I’m wrong. Hope this helps!

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2 years ago

The table below shows the distribution of students by age in a high school

harkovskaia [24]

Answer: 28

Step-by-step explanation:

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2 years ago

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For the function y=3x^2-12x+4 , what’s the mirroring point for the y-intercept? (x,y) form please

Slav-nsk [51]

Answer:

the you run y=3

Step-by-step explanation:

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3 years ago

Can somebody please explain and answer this for me? I really don't get it.

Tcecarenko [31]

Answer:

Results can be $(-\frac{1}{3} )^5$

Step-by-step explanation:

-The solution for this question:

$(-\frac{1}{3} )^5$ is equal to $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$

-The calculation for $(-\frac{1}{3} )^5$ :

$(-\frac{1}{3} )^5 = -\frac{1}{243}$

3 0

3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago