Given that a parking lot contains 100 cars, k of which happen to be lemons.
This is a conditional probability question.
Let event A be that a car is tested and event B be that a car is lemon.
The probability that a car is lemon is given by

The probability that a car is tested is given by

The probability that a car is lemon and it is tested is given by

For a conditional probability, the probablility of event A given event B is given by:

Therefore, the probability that a car is lemon, given that it is tested is given by.
The permutation shows that when one has been cast yet, the different ways that are there to cast Fantine from the 28 women is 28.
<h3>How to calculate the value?</h3>
The different ways that are there to cast Fantine from the 28 women will be:
= 28!/(28 - 1)!
= 28!/27!
= 28
When Fantine has already been cast, the number of ways that are there to cast adult Cosette from the remaining women will be:
= 27!(27 - 1)!
= 27!/26!
= 26
When Fantine and adult Cosette have already been cast, the different ways that are there to cast Éponine from the remaining women is:
= (28 - 2)!/(28 - 2 - 1)!
= 26!/25!
= 25
Learn more about permutations on:
brainly.com/question/4658834
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To solve this, subtract 6 from both sides of the greater than sign to get..
x is greater than -4
Answer:
131072
Step-by-step explanation:
Let's put it into expression form and simplify as much as possible :
=
=
131072
Hope this helped and have a good day