State and explain poiseuilles formula

1 answer:

3 0

The Poiseuille's Law formula is given by:
The Pressure Gradient (∆P) Shows the pressure differential between the two ends of the tube, defined by the fact that every fluid will always flow from the high pressure (P1) to the low-pressure area (P2) and the flow rate is calculated by the ∆P = P1-P2.

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Uma chapa metálica, com um furo central de diâmetro "d", é aquecida dentro de um forno. Com o aumento da temperatura, podemos af

Tatiana [17]

Answer: O furo diminui enquanto a chapa aumenta a sua dimensão.

(The diameter decreases and the dimensions of the metal increases)

Explanation:

I will answer in English:

Here we have a piece of metal with a small hole on it, that is heated in a hoven.

We know that when a piece of metal is heated, it will expand (the density decreases, so the dimensions of the piece of metal increase).

Now, particularly, the hole will also expand but inwards, as each "extreme" of the piece of metal, will expand into where it has less resistance, so it will expand in the region where there is no material. This "inwards" expansion is why the diameter of the hole will decrease.

4 0

3 years ago

An object is realsed From rest . how far does it fall during the second second of fall?

Savatey [412]

Answer:

14.715 m

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards, take downwards as positive

First second:

v = u + at

v = 9.81 m/s

Second second:

s = ut + (1/2)at^2

s = 9.81(1) + (1/2)(9.81)(1)^2

s = 14.715 m

6 0

3 years ago

distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.

a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

$v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s$