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drek231 [11]
2 years ago
10

Question 9 of 10 Which of these groups of values plugged into the TVM Solver of a graphing calculator will return the same value

for PV as the expression ($505)((1+0.004) - 1) ? (0.004)(1+0.004) Question 9 of 10 Which of these groups of values plugged into the TVM Solver of a graphing calculator will return the same value for PV as the expression ( $ 505 ) ( ( 1 + 0.004 ) - 1 ) ? ( 0.004 ) ( 1 + 0.004 )​
Mathematics
1 answer:
hodyreva [135]2 years ago
7 0

The TVM solver is a tool found in graphing calculators, that solve Time Value of Money problems.

The group of values that will return the same value as the given expression is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

<h3>What is Present Value?</h3>

Present value (PV) formula finds application in finance to calculate the present day value of an amount that is received at a future date.

In the TVM solver, we have;

I = The annual percentage rate

N = n × t

t = The number of years

PV = Present value

PMT = Payment

P/Y = Number of payments per year = n

C/Y = Number of compounding periods per year = n

The formula for monthly payment is presented as follows;

P = \frac{M[(1+r/n)^{nt} - 1]}{(r/n)(1+r/n)^{nt}}

M = \frac{P.(r/n)(1+ r/n)^{nt} }{(1+ r/n)^{nt} - 1}

Therefore, we get;

Where;

M = PMT = -415

P = PV

r = I

P/Y = n = 12

Therefore;

0.003 = I/12

I = 0.003 X 12 = 3.6%

N = n X t = 24

The value of the equation is the present value, PV = ?

When payment are made based on the PV, we have FV = 0

The group of values the same value as the expression

P = \frac{(415)[(1+0.003)^{24}-1]}{(0.003)(1+0.003)^{24}}

when plugged into the TVM solver of a calculator is;

D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END

Learn more about Present Value Solver from:

brainly.com/question/1759639

#SPJ1

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Numbers that add to -0.5 and multiply to 1
Oliga [24]
Short Answer
There are two numbers
x1 = -0.25 + 0.9682i   <<<< answer 1
x2 = - 0.25 - 0.9582i   <<<< answer 2 
 
I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5    
y = - 0.5 - x       (1)
xy = 1               (2)

Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1               Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0          Order these by powers
-x^2 - 0.5x -1 = 0           Multiply though by - 1
x^2 + 0.5x + 1 = 0         Use the quadratic formula to solve this.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 0.5
c = 1


\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add  as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out.  Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375

Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

The final result is 0.9375 and 0.0625 add up to 1
 
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