He should use 48 tablespoons of flour in his recipe.
Question 9
Given the segment XY with the endpoints X and Y
Given that the ray NM is the segment bisector XY
so
NM divides the segment XY into two equal parts
XM = MY
given
XM = 3x+1
MY = 8x-24
so substituting XM = 3x+1 and MY = 8x-24 in the equation
XM = MY
3x+1 = 8x-24
8x-3x = 1+24
5x = 25
divide both sides by 5
5x/5 = 25/5
x = 5
so the value of x = 5
As the length of the segment XY is:
Length of segment XY = XM + MY
= 3x+1 + 8x-24
= 11x - 23
substituting x = 5
= 11(5) - 23
= 55 - 23
= 32
Therefore,
The length of the segment = 32 units
Question 10)
Given the segment XY with the endpoints X and Y
Given that the line n is the segment bisector XY
so
The line divides the segment XY into two equal parts at M
XM = MY
given
XM = 5x+8
MY = 9x+12
so substituting XM = 5x+8 and MY = 9x+12 in the equation
XM = MY
5x+8 = 9x+12
9x-5x = 8-12
4x = -4
divide both sides by 4
4x/4 = -4/4
x = -1
so the value of x = -1
As the length of the segment XY is:
Length of segment XY = XM + MY
= 5x+8 + 9x+12
= 14x + 20
substituting x = 1
= 14(-1) + 20
= -14+20
= 6
Therefore,
The length of the segment XY = 6 units
Answer: A. 14
Step-by-step explanation:
If e=9 and c=5 you would replace e+c with those
9+5=14
Answer:
y = 3x +4
Step-by-step explanation:
The equation for the parallel line will have the same x- and y-coefficients, but a different constant. You can put the given point values into the equation to see what the constant needs to be:
y = 3x + b
10 = 3·2 + b . . . . . . substitute x=2, y=10
4 = b . . . . . . . . . . . . subtract 6
The equation of the line is ...
y = 3x +4
Let n be the amount of 80% solution; and 150-n be the amount of 20% solution. Then:
.8n+.2(150-n)=.6(150)
.8n+30-.2n=90
.6n=60
n=100
150-n=50
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