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adelina 88 [10]
3 years ago
11

3(5j+2)=2(3j-6) how do i do this

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0
Hello there!

To make this problem easier, let's get rid of the parenthesis by distributing the 3 and the 2!

3 (5j+2) becomes (3•5j) + (3•2) = 15j+ 6

2 (3j-6) becomes (2•3j) + (2• -6) = 6j-12

** be careful with the negative signs!!


So now you have:

15j+6 = 6j-12

Now, you simply move the numbers with the letters to one side of the equation. It doesn't matter which side.

15j - 6j = -12 - 6

Notice how when I bring over 6j the sign flips. It becomes -6j because you're subtracting it. When you do anything to one side of the equation, you must do the same to the other! :)

So now:

9j = -18

Now you divide both sides by 9! Why 9? Because 9 has a j attached to it. You're trying to solve for j (the value of the variable/letter).

So it's:

j = -2

And that's your answer!

I hope this helped!! :D

Tip: If you're still confused on when to subtract or divide, I suggest going to Khan Academy to watch their videos on Algebra 1, or just searching up similar problems on YouTube. :) Do whatever works for you!

------------


DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
ohaa [14]3 years ago
5 0

3(5j+2)=2(3j-6) do distributed to remove parenthesis  15j+6=6j-3 . Then move all j to left side and the second term to right side 15j-6j=-3-6. Now solve both sides  9j= -9. Now divide both sides by 9 to get j alone to j =  -1

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2

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(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

ANswer:

(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

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