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SIZIF [17.4K]
3 years ago
14

Find the value of x.

Mathematics
2 answers:
zmey [24]3 years ago
8 0
Sin30=opposite side/hypotenuse side
=>1/2=X/25
=>12.5=x
Hope This helps u...!!
zaharov [31]3 years ago
6 0

x = 25 \sin 30 = 25 (1/2) = \dfrac{25}{2}

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Find the mass of ether which can be put into a beaker holding 130ml
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Rachel,Timothy, and Robyn each make the rectangle prism shown. If they stand all of their prisms together, side by side, to make
Vladimir79 [104]

Answer: Multiple Answers...

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4 0
3 years ago
The following equation involves a trigonometric equation in quadratic form. Solve the equation on the interval [0,2π).
Effectus [21]

Answer:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

Step-by-step explanation:

Given the quadratic equation as:

2sin^2x+sinx=1\\OR\\2sin^2x+sinx-1=0

Let us put sinx=y for simplicity of the equation:

Now, the equation becomes:

2y^2+y-1=0

Now, let us try to solve the quadratic equation:

\Rightarrow 2y^2+2y-y-1=0\\\Rightarrow 2y(y+1)-1(y+1)=0\\\Rightarrow (2y-1)(y+1)=0\\\Rightarrow 2y-1 = 0, y+1 = 0\\\Rightarrow y = \dfrac{1}{2}, y = -1

So, the solution to the given trigonometric quadratic equation is:

sinx = \dfrac{1}{2}

and

sinx=-1

Let us try to find the values of x in the interval [0, 2\pi).

sin\theta can have a value equal to \frac{1}{2} in 1st and 2nd quadrant.

So, x can be

30^\circ, 150^\circ\\OR\\\dfrac{\pi}{6}, \dfrac{5\pi}{6}

For sinx=-1,

x = 270^\circ\ or\ \dfrac{3 \pi}{2}

So, the answer is:

\dfrac{\pi}{6}, \dfrac{5\pi}{6}, \dfrac{3\pi}{2}

7 0
3 years ago
Plz help for 60 points
ycow [4]
4. 22 
5. 37
6. 108
7. 494
8. 168
 
I am not sure what seven is since the picture has cropped it out, sorry. Hope this helps! 

Happy learning! - Ann

8 0
4 years ago
Read 2 more answers
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