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SIZIF [17.4K]
3 years ago
14

Find the value of x.

Mathematics
2 answers:
zmey [24]3 years ago
8 0
Sin30=opposite side/hypotenuse side
=>1/2=X/25
=>12.5=x
Hope This helps u...!!
zaharov [31]3 years ago
6 0

x = 25 \sin 30 = 25 (1/2) = \dfrac{25}{2}

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Evaluate 4 a + 5 b when a=3 and b= -1.2
Basile [38]

Answer:

6

Step-by-step explanation:

Plug the values of a and b into the equation.

4(3) + 5(-1.2)

12 + (-6)

Adding negatives basically means subtracting, so...

12-6 = 6

Therefore your answer is 6

Hope this helps!

3 0
2 years ago
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If x ≥ 0 and y ≥ 0, then which quadrant holds the solution?
Tju [1.3M]
Quadrent 1 because they are both positive numbers
5 0
3 years ago
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A line includes the points (1, 9) and (0, 5). What is it’s equation in the slope-intercept form?
scoundrel [369]

Equation is y = 4x + 5

Step-by-step explanation:

  • Step 1: Find the slope of the line by m = (y2 - y1)/(x2 - x1). Here y2 = 5, y1 = 9, x1 = 1 and x2 = 0

⇒ m = (5 - 9)/(0 - 1) = 4

  • Step 2: Find y-intercept, b. Since the line passes through (0, 5) b = 5
  • Step 3: Write the equation in slope-intercept form

⇒ y = 4x + 5

5 0
3 years ago
7th grade math. answer ASAP. If you answer correctly i will give thx, 5 star, and brainliest
Viktor [21]
Okay. First thngs first, let's divide each of them. 2.6/1.3 is 2. Now in terms of exponents, we would just simply subtract the powers, because we are doing division. 9 - 2 is 7. The value of the expression is 2 * 10^7. Even writing the problem out in number form (2,600,000,000/130), you can still see the answer to the problem as 20 million. The answer is B.
8 0
3 years ago
Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
2 years ago
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