Question

450g of chromium (III) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS: 6.0x10˄2 g K2SO4)

Answer 1

Answer:

599.26 grams of potassium sulfate will be produced.

Explanation:

$Cr_2(SO_4)_3(aq)+2K_3PO_4(aq)\rightarrow 2CrPO_4(s)+3K_2SO_4(aq)$

Moles of chromium (III) sulfate = $\frac{450 g}{392 g/mol}=1.1480 mol$

According to reaction, 1 mole of chromium (III) sulfate gives 3 moles of potassium sulfate.

Then 1.1480 moles of chromium (III) sulfate will give:

$\frac{3}{1}\times 1.1480 mol=3.4440 mol$

Mass of 3.4440 moles of potassium sulfate:

= 3.4440 mol × 174 g/mol = 599.26 g

599.26 grams of potassium sulfate will be produced.