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Afina-wow [57]
3 years ago
8

Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.

9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. View Available Hint(s) Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. 86.3529 amu 84.9118 amu 85.9105 amu 85.4681 amu
Chemistry
1 answer:
yarga [219]3 years ago
3 0

Answer:

85.4681  amu

Explanation:

We shall take weighted average of isotopes

Atomic mass of Rubidium

=\frac{.7215\times 84.9118 + .2785\times 86.9092}{.7215+.2785 }

= 61.26386 + 24.2042122

= 85.4681  amu .

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Mandarinka [93]

Answer:

a. 211.7

Explanation:

Iron Pyrite reacts with Oxygen to produce Iron (II) Oxide and Sulphur (IV) Oxide.

The equation is as follows:

4FeS₂₍s₎ + 11O₂₍g₎ → 2Fe₂O₃₍s₎ + 8SO₂₍g₎

From the equation, 4 moles of FeS₂ produce 8 moles of SO₂.

Therefore the reaction ratio is 4:8 or 1:2

198.20 grams of FeS₂ into moles is calculated as follows:

Moles= Mass/RMM

RMM of FeS₂ is 119.9750g/mol.

Number of moles = 198.20/119.9750g/mol

=1.652 moles of FeS₂

The reaction ratio of FeS₂ to SO₂ produced is 1:2

Thus SO₂ produced = 1.652 moles×2/1=3.304 moles

The mass of SO₂ produced =Moles ×RMM

=3.304 moles ×64.0638 g/mol

=211.667 grams

=211.7g

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