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Afina-wow [57]
3 years ago
8

Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.

9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. View Available Hint(s) Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. 86.3529 amu 84.9118 amu 85.9105 amu 85.4681 amu
Chemistry
1 answer:
yarga [219]3 years ago
3 0

Answer:

85.4681  amu

Explanation:

We shall take weighted average of isotopes

Atomic mass of Rubidium

=\frac{.7215\times 84.9118 + .2785\times 86.9092}{.7215+.2785 }

= 61.26386 + 24.2042122

= 85.4681  amu .

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A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

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According to stoichiometry:

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Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

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According to stoichiometry:

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Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

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2 years ago
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almond37 [142]

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