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egoroff_w [7]
2 years ago
11

How many moles of Fe(OH)3 are produced when 85.0 L of iron(3) sulfate at a concentration of 0.600 mol/L reacts with excess NaOH

Chemistry
1 answer:
patriot [66]2 years ago
4 0

Answer:

e = Mc hammer.

Explanation:

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2n² rule:

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drek231 [11]

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

PV=nRT

<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, P=1\rm atm

The volume of the gas has been, V= 0. 500 \;\rm  L

The temperature of the gas has been, T=15^\circ \text C\\&#10;T=288\;\rm K

Substituting the values for the moles of gas, <em>n:</em>

<em />

<em />\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\&#10;\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\&#10;\textit n=0.021\;mol

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
brainly.com/question/8711877

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