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egoroff_w [7]
3 years ago
11

How many moles of Fe(OH)3 are produced when 85.0 L of iron(3) sulfate at a concentration of 0.600 mol/L reacts with excess NaOH

Chemistry
1 answer:
patriot [66]3 years ago
4 0

Answer:

e = Mc hammer.

Explanation:

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What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

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How do you find the molecular formula from the empirical formula?
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What volume of a 0.200 M HCI solution is needed to neutralize 25.0 L of a 0.250 M NaOH solution? Follow these steps
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