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Solnce55 [7]
2 years ago
6

Will favor dissolution and

Chemistry
1 answer:
Marizza181 [45]2 years ago
8 0

Answer:

b) heating, cooling

Explanation:

Heating will favour dissolution (it helps dissolving faster).

Cooling helps in crystallization.

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PLEASE HELP ASAP
V125BC [204]

Answer:

third one

Explanation:

5 0
3 years ago
What is the definition of light in one sentence
bulgar [2K]

The dictionary definiton of light is:

the natural agent that stimulates sight and makes things visible.

I'll paraphrase/give a scientific definition:

Light is made of subatomic particles called photons, which jumps electron shells when they're excited, effecting the electromagnetic spectrum, creating visible light.

Hope this helps. Might not as I'm not perfect on this topic yet.

4 0
3 years ago
4. How many joules of heat are absorbed to raise
hodyreva [135]

. How many joules of heat are absorbed to raise

the temperature of 37 grams of water from 25°C

to 75°C?

7 0
2 years ago
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0
3 years ago
Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

6 0
3 years ago
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