Answer:
Explanation:
Given that,
A spring is compressed by 0.1 cm or 0.001 m
The spring constant of the spring, k = 100 N/m
The elastic potential energy in the spring is given by :
So, the elastic potential energy of the spring is equal to .
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Answer:
166.67 N
Explanation:
Applying Pascal's principle,
Presure in the smaller piston(P') = Pressure in the bigger piston(P)
But,
Pressure = Force/Area
Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')
Pressure in the bigger piston(P) = Force applied to the bigger piston(F)/Area of the bigger piston(A)
F'/A' = F/A.................. Equation 1
Make F the subject of the equation
F = F'A/A'.............. Equation 2
From the question,
Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²
Substitute these values into equation 2
F = 20(1000)/120
F = 166.67 N
Answer:
R = 4.18 * 10^8ohms
Explanation:
R=resistance in ohms=?
ρ=resistivity of material in ohms meters = 1.68*10^-8 oh ohm meters
L= length of the object (m) = 4.4m
A = cross-sectional area of the object in square meters (m^2)= πr^2
r = (1.5mm/1000)/2= 0.00075m
A=π*(0.00075)^2 = 1.76714586764426*10^-6
Approximately, A = 1.767m^2
R = ρL/A= (1.68*10^8Ω⋅m) * (4.4m)/(1.767m^2)
R = 418336162.988115 ohms
Approximately, R = 4.18 * 10^8ohms.