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alina1380 [7]
2 years ago
13

How do we calculate the "range" of the measurements?

Physics
2 answers:
Crazy boy [7]2 years ago
7 0

Answer:

The correct option is A

Explanation:

In a given set of data, the range is the difference between the highest value in the data and the lowest value in the same data. It can be determined by subtracting the smallest value from the largest value as shown below.

Consider the data below,

45,34,22,34,45,46,55,23,56,56,46,55,56,66,37,55,56,64,53,52,56,46,70

The range of the data above is

Largest value (70) - smallest value (22)

70 - 22 = 48

alexandr402 [8]2 years ago
5 0
The answer is A! You subtract the minimum from the maximum
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A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

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4 0
3 years ago
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Help with either I don’t understand this I know W=f*d but don’t get how it applies here
rosijanka [135]

Answer:

5) Displacement = +3.125 m

Displacement is in the same direction as the force vector.

6) Force = -53.89 N

Force is in an opposite direction relative to the displacement.

Explanation:

5) We are given;

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Now, formula for workdone is;

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Thus, displacement = Work/force

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Thus, displacement is in the same direction as the force vector.

6) We are given;

Displacement; d = 18 m.

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Like in the first answer above,

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Thus;

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Force = -970/18

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3 0
2 years ago
I need help PLEASE HEEEEEEEEELPP
lana66690 [7]

Answer:

a = (v2 - v1) / t

From A to B    (8 - 4) m/s / 1 s = 4 m / s^2

From A to D    ( 7 - 4) m/s / 5 s = .6 m / s^2

Note these equations hold for "uniform" values

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2 years ago
Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and
dexar [7]

Kepler’s
third law formula: T^2=4pi^2*r^3/(GM)

We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496
× 10^11 m)^3/((6.674× 10^-11N*m^2/kg^2)*(365.26days)^2)

M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work
with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

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=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel
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1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/(
86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The
closest answer is 1.99
× 10^30

(it may vary
a little with rounding – the difference is less than 1%)


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iVinArrow [24]
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