3 years ago

What is the difference b/w distance and displacement?

1 answer:

4 0

Distance is the actual path covered and displacement is the shortest distance from the object to the point of origin.

Please mark as brainliest if satisfied with answer

You might be interested in

According to the picture, how would the gravitational potential energy of the car change if its weight was doubled? A) The gravi

Lorico [155]

Answer is A

Samuriguy125 on YT

3 0

3 years ago

Read 2 more answers

if you use the compound pulley, you will need to pull twice the distance but with less force. the force you need is equal to one

algol13

Answer:

F= 25/2 = 12.5N

Explanation:

When you use a compound pulley the force required depends on the mechanical advantage of the compound pulley. This is known as rate of loss of distance or the ratio of the force to the load.

M.A = Effort distance /Load distance. OR M.A = Load/Effort

6 0

3 years ago

9.(7 +1) Line I 9.7 +9.1 Line 2 The expression was rewritten using the Distributive Property 9. (7 + 1) equals 9. 7 which equals

zhenek [66]

Answer:

Sorry

Explanation:

I really don't know what to say about this question I am not sure what to say about this

3 0

3 years ago

A constant-volume perfect gas thermometer indicates a pressure of 6.69 kPa at the triple point temperature of water (273.16 K).

mina [271]

Answer:

(a) ΔP=0.0245 kPa

(b) P=9.14 kPa

(c)ΔP=0.0245 kPa

Explanation:

(a) As it is perfect gas we can use

(P₁V₁)/T₁=(P₂V₂)/T₂

Since this constant volume so

P₁/T₁=P₂/T₂

T₂ is change in temperature

T₂=1.00+273.16

T₂=274.16 K

$P_{2}=(\frac{6.69}{273.16} )*274.16\\P_{2}=6.71449 kPa$

ΔP=6.71449-6.69

ΔP=0.0245 kPa

(b) As

$P_{2}=(\frac{6.69}{273.16} )*373.16\\P_{2}=9.14 kPa$

(c) Same steps as in part (a)

$P_{2}=(\frac{9.14}{373.16} )*374.16\\P_{2}=9.164kPa$

ΔP=9.164-9.14

ΔP=0.0245kPa

8 0

3 years ago

A small branch is wedged under a 200 kg rock and rests on a smaller object. The small object that creates a pivot point is calle

KiRa [710]

Answer:

F = 326.7 N

Explanation:

given data

mass m = 200 kg

distance d = 2 m

length L = 12 m

solution

we know force exerted by the weight of the rock that is

W = m × g ..............1

W = 200 × 9.8

W = 1960 N

and

equilibrium the sum of the moment about that is

∑Mf = F(cos∅) L - W (cos∅) d = 0

here ∅ is very small so cos∅ L = L and cos∅ d = D

so F × L - W × d = 0 .................2

put here value

F × 12 - 1960 × 2 = 0

solve it we get

F = 326.7 N

8 0

3 years ago

Read 2 more answers