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tangare [24]
4 years ago
13

Car A is 16 kilometers to the west of car B. At noon, Car A begins driving east at a constant speed 4 kilometers/hour, and car B

begins driving north at a constant speed of 3 kilometers/hour. (a) (5 points) Let x be the distance that car A has traveled since noon, and let y be the distance that car B has traveled since noon. Let z be the distance between the two cars. Find an equation that relates x to x and y.
Physics
1 answer:
Vladimir [108]4 years ago
3 0

Answer:

The distance traveled can be found by kinematics equations

x = vt

x(t) = v_At - 16= 4t - 16\\y(t) = v_Bt = 3t\\z(t) = \sqrt{x(t)^2 + y(t)^2} = \sqrt{16t^2 - 128t + 256 + 9t^2} = \sqrt{25t^2 - 128t + 256}

Explanation:

The initial position of Car B is denoted as origin. Car A started at -16 km, and moving right. Car B started at origin and moving up. z is the magnitude of the vector with components x and y.

The relation can be found by pythagorean theorem.

For checking the solution, we can find the positions at t = 4h. Car A is at the origin, and Car B is 12 km north of origin. z = 12.

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5 0
3 years ago
Read 2 more answers
A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang
12345 [234]

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

F_{Net} = ma

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

F_{Net} = T-mg = a(m_1+m_2)

186.2 - 138.12 = a(15+19)

48.08 =  a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

7 0
4 years ago
A wrecking ball has a mass of 650 kg. it swings from a cable that is 21 m long. the centripetal force on the ball is 56 n. what
sweet-ann [11.9K]
The correct answer was A "1.3 m/s"
7 0
3 years ago
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A soccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. If the ball lands at the same level fro
Lisa [10]

Answer:

2.57 seconds

Explanation:

The motion of the ball on the two axis is;

x(t) = Vo Cos θt

y(t) = h + Vo sin θt - 1/2gt²

Where; h is the initial height from which the ball was thrown.

Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²

We want to find the time t at which y(t) = h

Therefore;

y(t) = h + Vo sin θt - 1/2gt²

Whose solutions are, t = 0, at the beginning of the motion, and

t = 2 Vo sinθ/g

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3 years ago
A parallel plate capacitor is made of two large plates ofarea
Murrr4er [49]

Answer:

C = \frac{\epsilon_0 \epsilon_1 A}{\epsilon_0 t + \epsilon_1(a-t)}\\

Explanation:

If there is a dielectric slab with thickness less than the distance between the plates is inserted inside a capacitor, then that capacitor can be regarded as two capacitors connected in series.

Let's assume that the slab is placed onto the lower side. So, the capacitance of that part of the capacitor, C1 is

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where \epsilon_1 is the permittivity of the slab.

The other part of the capacitor is

C_2 = \epsilon_0 \frac{A}{a-t}

Two capacitors are connected in series:

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C = \frac{Q}{V_0}

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3 years ago
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