a. The circulatory system in fish is one-directional while it is two-directional in humans.
b. P has a high concentration of carbon dioxide and low oxygen concentration whereas Q has high oxygen concentration and low carbon dioxide concentration.
<h3>What is the circulatory system?</h3>
The circulatory system is the system of organism and tissues which help to transport blood and other fluids through the body of a living organism.
The organs of the circulatory system include:
- The heart
- The blood vessels - veins, arteries, capillaries
a. In the given diagram sowing the circulatory system of man and the fish, it can be seen that the direction of blood flow in the fish is one way through the heart. However, in humans, the direction of blood flow is two-way through the heart.
b. The gas in P has a high concentration of carbon dioxide and low oxygen concentration. However, the gas flowing through Q has high oxygen concentration and low carbon dioxide concentration.
In conclusion, the circulatory system is important in the exchange of gases in the body.
Learn more about circulatory system at: brainly.com/question/3597250
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The mass number refers to the total number of protons and neutrons which can be found in the nucleus of the atom.
Burning Mg in the air and reacting with O2 forming a white powder of MnO
So the equation is going to be:
Mn + O2 ⇒ MnO (this equation is not conserved)
to make it equilibrium:
1- First we should put 2Mno to equal the O2 on both sides.
So it will be:
Mg + O2⇒ 2MgO
2- Second we should put 2Mn to equal the Mn on both sides.
2Mg + O2⇒ 2MgO (this equation is conserved)
After putting the physical states the final equilibrium equation is going to be:
Δ
2Mg(s) + O2(g)⇒ 2MgO(s)
Answer:
<em>The correct option is a) Precipitate: silver sulfate
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<em>Net Ionic: 2Ag+ + SO42 →Ag2SO4</em>
Explanation:
When sodium sulfate reacts with silver nitrate, the following reaction occurs:
2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3
The NaNO3 is easily soluble in water. However, silver ions form an insoluble solid with SO4. The Ag+ in this compound will be a cation having a positive charge. The SO4- will be an anion having an negative charge.
The table with solubility rules show that the sulfates of Ag+, Ca+, Sr2+, Ba2+, Hg22+ and Pb2+ are insoluble.
Answer:
Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O
The reactants are present in equimolar amounts, so there is no excess or limiting reactants.
(0.0500 L) x (0.600 mol/L HCl) x (2 mol H2O / 2 mol HCl) = 0.0300 mol H2O
(4.184 J/g·°C) x (50.0 g + 50.0 g) x (25.82 - 21.73)°C = 1711.256 J
(1711.256 J) / (0.0300 mol H2O) = 57042 J/mol = 57.0 kJ/mol H2O
Explanation:
