Answer:
0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).
Explanation:
<em>d = m/V,</em>
where, d is the density of the material (g/cm³).
m is the mass of the material (m = 28 g).
V is the volume of the material (V = 63.0 cm³).
<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>
Answer:
8.11g
Explanation:
Given parameters:
Molarity of aqueous solution = 0.3M
total volume = 0.15L
Molecular weight of glucose = 180.6g/mol
Unknown:
Mass of glucose needed in the solution = ?
Solution:
To solve this problem, we need to understand molarity.
Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.
Molarity = 
A solution is made up of solute and solvent.
now, let us solve for the number of moles of the solute which is glucose;
Number of moles of glucose = molarity x volume of solution;
= 0.3 x 0.15
= 0.045mole
Now to find the mass of glucose;
mass of glucose = number of moles x molar mass
input the parameters;
Mass of glucose = 0.045 x 180.16 = 8.11g
Answer:
The rate of dissolution for a solid solute when cease of stirring is typically: B. It is decreased
Explanation:
The rate of dissolution for a solid solute decreases when you stop stirring it.
Which of the following are supported by many observations
A- hypothesis
B- laws
C- theories
Laws and Theories
Mass would crystallize out : 24 g
<h3>Further explanation
</h3>
Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility
-
1. Temperature:
-
2. Surface area:
-
3. Solvent type:
-
4. Stirring process:
We can use solubility graph to solve this.
solubility KClO₃ at 90°C=52 g
solubilty KCl₃ at 60°C= 28 g
Mass would crystallize out = 52 - 28 =24 g