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Varvara68 [4.7K]
3 years ago
13

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

108 cm²

Step-by-step explanation:

The lateral area of this pyramid is the addition of the six triangle areas formed on its lateral side.

The area of each triangle is:

Area = (1/2)*side*slant

Area = (1/2)*3*12 = 18 cm²

Then the lateral area is 6*18 = 108 cm²

sergeinik [125]3 years ago
7 0

i think you do it by like

12squared - 1.5 squared = A Squared

you do this to get the height

so

144- 2.25 = 141.75 then you square root it which equals 11.90

11.90×3÷2 = 17.85

17.85×6= 107. 15

im not sure

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A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

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Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

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