So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.
Answer:
C. 2• 3 • x • x
Step-by-step explanation:
Not sure but that's what I would guess
4ab^2
Hoped this helps! Just had it on a quiz and got it right. If you have boxex by 4 a^1 b^2
The questions is asking which one and i say is graph B
Answer:
Step-by-step explanation:
Opposite angles in an inscribed quadrilateral are supplementary, so ...
∠B +∠D = 180°
(3x -4) +(2x -6) = 180
5x = 190 . . . . . . . . . . . add 10, collect terms
x = 38 . . . . . . . . . . . . . divide by 5
∠D = 2(38) -6 = 70
∠B = 180 -70 = 110
The measures of angles B and D are 110° and 70°, respectively.