Question

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Answer 1

Answer:

108 cm²

Step-by-step explanation:

The lateral area of this pyramid is the addition of the six triangle areas formed on its lateral side.

The area of each triangle is:

Area = (1/2)*side*slant

Area = (1/2)*3*12 = 18 cm²

Then the lateral area is 6*18 = 108 cm²

Answer 2

i think you do it by like

12squared - 1.5 squared = A Squared

you do this to get the height

so

144- 2.25 = 141.75 then you square root it which equals 11.90

11.90×3÷2 = 17.85

17.85×6= 107. 15

im not sure