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kondor19780726 [428]
3 years ago
8

Andrew’s math teacher entered the seventh-grade students in a math competition. There was an enrollment fee of $30 and also an $

11 charge for each packet of 10 tests. The total cost was $151. How many tests were purchased?
use a tape diagram to solve and if-then statement
Mathematics
2 answers:
algol [13]3 years ago
4 0

Answer:

p=11 packets were purchased

Step-by-step explanation:

30+11p=151

11p=121

then

121/11

so

p=11

Hope I understood the question :/

otez555 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

I believe the correct answer is that Andrew's Math Teacher purchased 11 packets of 10 tests each, meaning that the total number of test would be 110. I got this by subtracting the $30 entrance fee from the $151. After doing this we are left with $121. I then divided the $121 by the cost per packet and I was left with 11 packets. Since every packet contains 10 tests I multiplied that by the number of packets to get the final answer... 110 tests purchased.

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Look at picture <br>y=_<br><br>the height of the baseball after 5 seconds is ___ feet​
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Answer:

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Step-by-step explanation:

We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...

  y = a(x -3)² +b

Filling in the values from the first two table points, we get

  For (x, y) = (0, 6):

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Subtracting the second equation from the first gives ...

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5 0
3 years ago
Solve the quadratic for x, then enter the numerical value of your solution. (If there are two solutions, either one will work.)
xz_007 [3.2K]

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Step-by-step explanation:

Step 1 : Equate ( x-5)² since it occurred twice, hence the reason 2 is added in front of (x-5)²

= (x-5)²

= (x-5)(x-5)

= (x²-5x-5x+25)

= (x²-10x+25)

Step 2: multiply the result by two since it occurs twice and also bring the equation

= 2 (x²-10x+25) +7 = 79

= 2x²- 20x+50+7 = 79

= 2x²- 20x+57 =79

Step 3: most quadratic equation are always equal to zero, let's make this one equal to Zero by subtracting 79 from both sides

= 2x²-20x+57-79 = 79-79

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Step 4: divide the equation by a common number to get the least coefficient of the three coefficients

Dividing the three by 2

(2x²-20x-22)/2 = x²- 10x- 11

Step 5: Factorise completely

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Sub step 2: multiply the coefficient of the first term (1) and the constant (-11) which gives us (-11)

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Step 6: slot the two numbers (+1, -11) into the equation by making themr replace the second coefficient

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Step 7: split the equation into two and Factorise further

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= x+1= 0 or x-11 =0

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= x+1= 0.

Subtract 1 from both sides

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Or X should be

= x-11=0

Add 11 to both sides

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