All categories

2 years ago

Solve the equation. 8(x + 6) = 43 What is the value of x?

Mathematics

2 answers:

Wewaii [24]2 years ago

7 0

Answer:

Exact form

5/8

Decimal form

0.625

Step-by-step explanation:

mixer [17]2 years ago

4 0

Answer:

-5/8 or -0.625

Step-by-step explanation:

divide both sides by 8

$\frac{8(x+6)}{8} =\frac{43}{8}$

Simplify

$x+6 = \frac{43}{8}$

Subtract 6 from both sides

$x+6 - 6 = \frac{43}{8} -6$

Convert the fraction to decimal and simplify

$5.375 - 6 = -0.625$

Simplified:

$-\frac{5}{8}$

Hope this helps

~R3V0

You might be interested in

Which value of a does not satisfy the inequality |al > 2a - 3 ?

Diano4ka-milaya [45]

Skhajwsgejwkwvwwiiww KB she

4 0

3 years ago

Work out the area of the circle and leave it in cm plz

Marat540 [252]

Answer:

132.7495 cm^2

Step-by-step explanation:

area of circle=πr^2

radius=6.5

6.5^2

42.25

42.25*3.142

132.7495

5 0

2 years ago

Read 2 more answers

If Clive was charged $3.92 for a minute 38 call, what is Clive's per minute base rate?

Tanzania [10]

Pretty sure it’s $0.10

8 0

2 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

Please help with this?

frez [133]

$7p3 = 210$

8 0

2 years ago

Solve the equation. 8(x + 6) = 43 What is the value of x?​

Solve the equation. 8(x + 6) = 43 What is the value of x?