ASAP WILL GIVE BRAINLIEST

Mathematics

2 answers:

wlad13 [49]3 years ago

4 0

Answer:

802.75 pi

Step-by-step explanation:

avanturin [10]3 years ago

4 0

Answer:

V≈ 2521.91 mm cubed

Step-by-step explanation:

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Through: (2,5), perp. to y =- 2/3x +3

chubhunter [2.5K]

Find the equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3

<h3><u>Answer:</u></h3>

The equation of line passes through point (2, 5) and perpendicular to line having equation y =- 2/3x +3 in slope intercept form is $y = \frac{3}{2}x + 2$

<h3><u>Solution:</u></h3>

Given that line passes through (2, 5) and perpendicular to line having equation $y = \frac{-2}{3}x + 3$

Let us first find slope of original line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form y = mx + c and given equation of line $y = \frac{-2}{3}x + 3$ we get

$m = \frac{-2}{3}$

Thus slope of given line is $m = \frac{-2}{3}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

Slope of given line x slope of line perpendicular to it = -1

$\begin{array}{l}{\frac{-2}{3} \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{3}{2}}\end{array}$