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d1i1m1o1n [39]
3 years ago
13

Need help please !!!!

Chemistry
1 answer:
Margaret [11]3 years ago
3 0

Answer:

2p

Explanation:

it has 3 dumbell shapes, hence p

you can't determine the principal quantum number by looking at the shape, however bigger or spread orbital means higher value of n

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What other simple sugars have the same chemical formula as glucose?
Usimov [2.4K]

Answer:

The answer to your question is:

Explanation:

Other sugars with the same chemical formula as Glucose:

Sugar            Formula            Description

Glucose         C₆H₁₂O₆            It's the most abundant monosaccharide.

Mannose       C₆H₁₂O₆            It's found in plants and some animals.

Fructose        C₆H₁₂O₆            It's the sugar of fruits.

Galactose      C₆H₁₂O₆            It's found in milk.

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3 years ago
Convert 3.2 ft^2 to square inches
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460.8 square inches

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HELP PLEASE <br><br> What makes up most of an<br> atom's volume, and where is it located?
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Explanation: hope this helped

4 0
3 years ago
The equilibrium constant for the reaction of fluorine gas with bromine gas at 300 K is 54.7 and the reaction is: Br2(g) + F2(g)
alisha [4.7K]

Answer:

The correct answer is 0.024 M

Explanation:

First we use an ICE table:

      Br₂(g)     +     F₂(g)    ⇔       2 BrF(g)

I      0.111 M          0.111 M                0

C      -x                   -x                      2 x

E      0.111 -x          0.111-x                2x

Then, we replace the concentrations of reactants and products in the Kc expression as follows:

Kc= \frac{[BrF ]^{2} }{[ F_{2} ][Br_{2}  ]}

Kc= \frac{(2x)^{2} }{(0.111-x)(0.111-x)}

54.7= \frac{4x^{2} }{(0.111-x)^{2} }

We can take the square root of each side of the equation and we obtain:

7.395= \frac{2x}{(0.111-x)}

0.111(7.395) - 7.395x= 2x

0.82 - 7.395x= 2x

0.82= 2x + 7.395x

⇒ x= 0.087

From the x value we can obtain the concentrations in the equilibrium:

[F₂]= [Br₂]= 0.111 -x= 0.111 - 0.087= 0.024 M

[BrF]= 2x= 2 x (0.087)= 0.174 M

So, the concentration of fluorine (F₂) at equilibrium is 0.024 M.

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