The percent yield of the industrial preparation of ozone is the 12%.
<h3>How do we calculate the percent yield?</h3>
Percent yield of any reaction will be calculated by using the below equation:
% yield = (Actual yield / Theoretical yield) × 100%
Given chemical reaction is:
3O₂(g) → 2O₃(g)
Moles of oxygen will be calculated as:
n = W/M, where
- W = given mass = 96kg = 96,000g
- M = molar mass = 32g/mol
n = 96,000/32 = 3000mol
From the stoichiometry of the reaction it is clear that:
3 moles of oxygen = produces 2 moles of ozone
3000 moles of oxygen = produces 2/3(3000)=2000 moles of ozone
Mass of 2000 moles of ozone = (2000mol)(48g/mol) = 96,000g = 96kg
Actual yield of ozone = 11.5kg (given)
Now percent yield will be calculated as:
% yield = (11.5 / 96) × 100% = 11.97% = 12%
Hence required percent yield is 12%.
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