Answer:
The answer to your question is:
Explanation:
Other sugars with the same chemical formula as Glucose:
Sugar Formula Description
Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.
Mannose C₆H₁₂O₆ It's found in plants and some animals.
Fructose C₆H₁₂O₆ It's the sugar of fruits.
Galactose C₆H₁₂O₆ It's found in milk.
Answer:Accounting for the sizes of protons, neutrons, and electrons, most of the volume of an atom—greater than 99 percent—is, in fact, empty space. ... The electrons that surround all atoms are negatively charged and cause atoms to repel one another, preventing atoms from occupying the same space.
Explanation: hope this helped
Answer:
The correct answer is 0.024 M
Explanation:
First we use an ICE table:
Br₂(g) + F₂(g) ⇔ 2 BrF(g)
I 0.111 M 0.111 M 0
C -x -x 2 x
E 0.111 -x 0.111-x 2x
Then, we replace the concentrations of reactants and products in the Kc expression as follows:
Kc= ![\frac{[BrF ]^{2} }{[ F_{2} ][Br_{2} ]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BBrF%20%5D%5E%7B2%7D%20%7D%7B%5B%20F_%7B2%7D%20%5D%5BBr_%7B2%7D%20%20%5D%7D)
Kc= 
54.7= 
We can take the square root of each side of the equation and we obtain:
7.395= 
0.111(7.395) - 7.395x= 2x
0.82 - 7.395x= 2x
0.82= 2x + 7.395x
⇒ x= 0.087
From the x value we can obtain the concentrations in the equilibrium:
[F₂]= [Br₂]= 0.111 -x= 0.111 - 0.087= 0.024 M
[BrF]= 2x= 2 x (0.087)= 0.174 M
So, the concentration of fluorine (F₂) at equilibrium is 0.024 M.
D. 1 and 3 only because you never taste, and a liquid cannot melt