Answer:
Theoretical yield = 40.8g
Explanation:
4Al + 3O2 ----] 2Al2O3
<h3>if 27.0g of Al ----] 102.0g of 2Al2O3</h3><h3>therefore 10.8g -----] xg</h3>
10.8g×102.0g/ 27.0g
theoretical yield = 40.8 g
Answer:
The answer is
<h2>34.02 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of lead = 3 mL
density = 11.34 g/mL
The mass of the lead is
mass = 3 × 11.34
We have the final answer as
<h3>34.02 g</h3>
Hope this helps you
Answer:
The new pressure is 2, 74 atm
Explanation:
We apply Boyle Mariotte's law, where for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1 = P2xV2 P2=( P1 x V1)/V2 1 L-----1000L--->( 140ml/1000ml)x1L=0,140 L
(50ml/1000ml)x 1L =0,050L
P2= (0,980 atm x 0,140 L)/0,050L= 2, 744 atm
Answer:
Percent yield = 89.1%
Explanation:
Based on the equation:
Cl₂ + 2KI → 2KCl + I₂
<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>
<em />
To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:
<em>Moles Cl₂:</em>
8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles
<em>Moles KI -Molar mass: 166.0028g/mol-</em>
25g * (1mol / 166.0028g) = 0.15 moles
Here, clarely, the KI is the limiting reactant
As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:
0.15 moles * (74.5513g / mol) =
11.2g KCl
Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100
<h3>Percent yield = 89.1%</h3>