Answer:
See explaination
Explanation:
See attachment for the structure of the acetal that you would obtain by reaction of cyclopentanone with 1-propanol.
2.0 grams of mass which would make the dimand
KOH + HBr ---> KBr + H2O
0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr
according to the reaction: 1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH
0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH
answer: 0,5 mol/dm³ KOH (molarity)
Answer: The amount of water formed is 12 moles
Explanation: Please see the attachments below