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Marrrta [24]
3 years ago
5

Vincent and 2 of his friends go to tge movies. A ticket costs $7.75. They decided to split the cost of the popcorn. If they eacg

spent $10.25, how much did the popcorn cost
Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

$7.50

Step-by-step explanation:

In this scenario, we know that they all spent the same amount on the ticket, and the same overall amount. Therefore we first subtract the total from the ticket amount to know how much each of them spent on popcorn (assuming they didn't make any more purchases).

10.25 - 7.75 = 2.50

So we can see that each member spent $2.50 on popcorn. Since there are three of them (Vicent and 2 friends) we simply multiply this number by 3 to find the total amount of the popcorn.

2.50 * 3 = 7.50

Finally, we can see that the Popcorn was worth $7.50

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Answer:

where's the picture bro?

Step-by-step explanation:

7 0
3 years ago
Identify the maximum or minimum value and the domain and range of the graph of the function y = 2(x + 2)2 - 3
klasskru [66]
I'm pretty sure the answer is B
3 0
2 years ago
I need help i'm really stuck
Ivenika [448]

Answer:

8

Step-by-step explanation:

If the area is 32 and the formula for area of a triangle is base * height / 2, and you have base = 8 and height = x and area = 32, this would be:

8 * x / 2 = 32

Now, solve:

8x/2=32\\4x=32\\x=8

4 0
2 years ago
Read 2 more answers
Andres boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rot
Gelneren [198K]

Answer:

a) r(t) = 0.783t radians

b) h(t) = 30cos(0.783*t) feet

Step-by-step explanation:

The situation is depicted in the picture attached

<h3>(see picture) </h3>

Since the angular speed is constant, to find an expression for the angle r(t) in radians we just cross-multiply using the fact that 1 min = 60 seconds

4.7 radians __________ 60 seconds

r(t) radians ____________  t seconds

\large \displaystyle\frac{4.7}{r(t)}=\displaystyle\frac{60}{t}\Rightarrow r(t)=(4.7/60)t \Rightarrow\\\\\boxed{r(t)=0.783t\;rad}

The height h(t) after t seconds is given by

h(t) = 30cos(r(t)) ===>

h(t) = 30cos(0.783*t) feet

7 0
2 years ago
The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
2 years ago
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