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azamat
3 years ago
14

the graph represents a function with the form f(x)=asin(bx+c) which values of a,b, and c are possible

Mathematics
1 answer:
love history [14]3 years ago
4 0

Answer:

a= 6,  b= 3,   c=pi

Step-by-step explanation:

2020 egdenuity just took the test

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cate and elena were playing a card game the stack of cards in the middle had 24 cards in it to begin wiht. Cate added 8 cards to
Kaylis [27]
24+8 = 30

30 - 12 = 18

18-9 = 8

There are 8 cards left in the stack
7 0
3 years ago
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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
Is -2x2y3z an expression or equation?
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Step-by-step explanation:

expressions DON'T have equal signs but equations do.

7 0
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Answer:

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Tip = $6.48

6 0
3 years ago
48÷479×390÷38789946=
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correct answer is 0.0000010075

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3 years ago
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