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natta225 [31]
3 years ago
12

Matt and Seth purchase baseball cards each week. the amount of cards they each have in their collection is shown in the graph an

d table. who will have more cards in week 20?

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

<u>In week 20, Seth will have 80 cards and Matt will have 60.</u>

Step-by-step explanation:

Let's find out the amount of cards that Math and Seth will have in week 20, using the information shown in the graph and table:

Amount of cards Seth has in week 20 = 20 * 4 = 80

The equation to find out the amount of cards, c, Seth has in week w:

c = 4w

Amount of cards Matt has in week 20 = 20 + (2 * 20) = 20 + 40 = 60

The equation to find out the amount of cards, c, Matt has in week w:

c = 20 + 2w

<u>In week 20, Seth will have 80 cards and Matt will have 60.</u>

Note: Same solution to question 14725490, answered by me today.

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If elf =gjh ef=12 and Lf=7.8 find ij
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Answer:

IJ= 4.98

Step-by-step explanation:

EF = 12

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LF = 7.8

LK = sqrt(7.8^2-6^2) = 4.98

IJ = LK (4.98)

8 0
3 years ago
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

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(x, y) → (-x, -y)

(4, 2) → (-4, -2)

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