1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitriy789 [7]
3 years ago
7

Determine the value of y.

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

D. 45°

Step-by-step explanation:

Since the lines are parallel, 2y°=90° If you divide both sides by 2, y°=45°

You might be interested in
Lena is converting 2/25 to a percent. What should she multiply the numerator and denominator of the fraction by to find the perc
NNADVOKAT [17]
A percent is a number out of 100, so you'd want to multiply the denominator to get 100. In this case, 25 would have to be multiplied by 4 to get 100. To keep the fractions equal to each other, you have to multiply the numerator by the same thing. 2*4=8. Therefore, your fraction would be 8/100 or 8%
7 0
3 years ago
Read 2 more answers
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
3 years ago
Read 2 more answers
Can you solve -3(y-5)=24
garri49 [273]

Answer:y=-3

Step-by-step explanation:yes firs multiply everything by -3 in parenthesies

Then you would subtract 15 from both sides

Next you would divide 9 by -3 and you would get -3

So y =-3

7 0
4 years ago
Read 2 more answers
The museum has lots of painting of the 465 paintings 302 are flower paintings the rest are painting of people how many paintings
den301095 [7]
163 paintings are paintings of people. 

465-302
   163
7 0
3 years ago
Read 2 more answers
A motorcycle shop maintains an inventory of four times as many new bikes. If there are 80 new bikes, how many used bikes are now
Ghella [55]
Answer: There are 20 used bikes



Explanation: If there are 4 times the used bikes then you would have to do 80 divided by 4 and there’s the answer
7 0
3 years ago
Read 2 more answers
Other questions:
  • Sketch the curve y=(3x-4)(4x-3)^2
    14·1 answer
  • Solve 3x2 + 4x = −5.
    6·2 answers
  • A circle has a radius of 6/7 units and is centered at (-2.3,0) What is the equation of the circle
    12·1 answer
  • Teri paid $3.06 for apples that cost $.68<br> a pound.How many pounds of apples did she buy?
    15·1 answer
  • Estimate.<br><br> 45.86 + 54.14<br> A. 90<br> B. 99<br> C. 100<br> D. 110
    8·1 answer
  • Pls help I fell asleep while doing hw and I gotta turn it in at 6 pls help. No false answers.
    8·1 answer
  • A room has a length of 12 metres and width of 5 metres. What is the area of the room?
    7·1 answer
  • What is 5/10 + 8/100
    12·1 answer
  • 9.2384E6 in standard form
    6·1 answer
  • Amelia, Shauna, Jamie, and Clarence used different approaches to solve this equation.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!