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AnnZ [28]
3 years ago
12

Which expressions are in simplest form? Check all that apply.

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer:

feels good doesn't it

Step-by-step explanation:

LenaWriter [7]3 years ago
7 1

Answer:

how the tables have turned

Step-by-step explanation:

thx for the points btw

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X an y are proportional. What is the missing value in the table <br>​
Leto [7]

Answer:

X+y

Step-by-step explanation:

6 0
3 years ago
This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the t
sergey [27]
Because it is an isosceles triangle, the two longer sides are the same length. Therefore multiply 6.3 times 2.
To find the length of the base subtract 12.6 from 15.7 to get 3.1 cm.
8 0
3 years ago
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Question 7 of 10<br> Choose two statements that are true for this expression.<br> 6r³ − 8x² - 40 +21
crimeas [40]

Based on the given parameters, bhe true statements are: the expression has four terms, and the term -40/y is a ratio.

<h3>How to determine the true statements?</h3>

The expression is given as:

6x^3 - 8x^2 - 40/y + 21

The above expression has four terms, and the terms are:

6x^3, - 8x^2,- 40/y and 21

Also, the term -40/y is a ratio

This is so because it is a quotient of two numbers

Hence, the true statements are: the expression has four terms, and the term -40/y is a ratio, based on the given parameters

Read more about polynomials at:

brainly.com/question/2833285

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4 0
1 year ago
In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.
marissa [1.9K]

Here, DH = HF 

x+3 = 3y

x = 3y-3   ----(I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is      x=3  & y=2



3 0
3 years ago
Read 2 more answers
Work out the size of AED. Work out x
Monica [59]

Answer:

a). m∠AED = 70°

b). x = 10°

Step-by-step explanation:

a). Quadrilateral ABDE is a cyclic quadrilateral.

Therefore, by the theorem of cyclic quadrilateral,

Sum of either pair of opposite angle is 180°

m(∠AED) + m(∠ABD) = 180°

m(∠AED) = 180° - 110°

m(∠AED) = 70°

Since, ∠AED ≅ ∠EAD

Therefore, m∠AED = m∠EAD = 70°

b). By triangle sum theorem in ΔABD,

m∠ABD + m∠BDA + m∠DAB = 180°

110° + 40° + m∠DAB = 180°

m∠DAB = 180° - 150°

m∠DAB = 30°

m∠BAE = m∠EAD + m∠BAD

              = 70° + 30° = 100°

By angle sum theorem in ΔACE,

m∠EAC + m∠AEC + m∠ACE = 180°

100° + 70° + x° = 180°

x = 180° - 170°

x = 10°

4 0
3 years ago
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