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nekit [7.7K]
2 years ago
10

Rewrite the following survey question to remove any bias:

Mathematics
1 answer:
bulgar [2K]2 years ago
4 0

Answer:

which do you prefer going, English or math class.

Step-by-step explanation:

You might be interested in
When creating lines of best fit, do you believe that estimation by inspection of the equation is best or do you think it should
Alex73 [517]

Answer:

Estimation by inspection is better than trying to determine the line of best fit exactly

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

Step-by-step explanation:

To create lines of best fit the estimation by inspection is better than trying to determine the line of best fit exactly .

This is because line of best fit only shows the trend of the data and in most cases it doesn't have to start from origin.

Scenarios :

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

8 0
3 years ago
the length of a rectangle is 2 cm more than 5 times the width. The perimeter 196 cm.Find the width and length
blondinia [14]

w(5)+2+w=196

5w+2+w=196

6w+2=196

6w=194

w=32 1/3

4 0
3 years ago
Make q subject of the formula 2(q+p) = 1+5q
m_a_m_a [10]

Answer:

expand the equation

then make q the subject of the formal

6 0
2 years ago
Y+5<br> ——=0 solve for y<br> X-1
Ira Lisetskai [31]

Answer:

y = -5

Step-by-step explanation:

see the pic for the steps . .

5 0
3 years ago
What’s the answer?and how do you get it
Kay [80]

the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.

from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.

the standing up sides are simply rectangles of 8x3.

if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312

7 0
3 years ago
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