Answer:
Option (A) is the right answer for factors.
Option (B) is the right answer for factor levels.
Explanation:
As per the scenario, the company wants to see the effect of their new website design on their customers, for which the factor of time spent on the new website is right because it gives the company to acknowledge the data of time spent by a customer on the new website.
To reach the result of the factor, we have to work on the factor level, in which we will compare the time spent on the old website and the new website because it gives the company an idea of customers preferring which website design.
Answer:
The Atos case demonstrates that it is possible to cut out e-mail entirely.
Explanation:
Answer:
Evidence based decision-making
Explanation:
Evidence-based decision-making uses research as the backbone for making decisions. It ensures that proper investigations are done before any decision is made.
This decision making technique carries out an in-depth analysis of empirical data collected from targeted sources. The decisions made are based on the following type of evidence:
- Ethical evidence: research based on social justice to guide in making ethical decisions.
- Statistical modeling: using regression methods to make decisions in organizations.
- Impact evidence: making investigations based on the impact on others.
- Implementation evidence: considering the implementation and delivery success, after proper investigation.
L.L. Bean works with the records of how quick customers make decisions and whether they complete their purchase. This means that they suggest solutions based on the evidence retrieved from the data.
Answer:
Merge sort is a sorting technique based on divide and conquer technique.
Explanation:
MERGE(A, p, q, r)
n1 = q - p + 1
n2 = r - q
L[1..n1] and R[1..n2] this creates the new array
for i = 1 to n1
L[i] = A[p + i - 1]
for j = 1 to n2
R[j] = A[q + j]
i = 1
j = 1
for k = p to r
if i > n1
A[k] = R[j]
j = j + 1
else if j > n2
A[k] = L[i]
i = i + 1
else if L[i] ≤ R[j]
A[k] = L[i]
i = i + 1
else
A[k] = R[j]
j = j + 1
