Answer:
AspNet.ScriptManager.jQuery?
Explanation:
Unobtrusive validation means we can perform a simple client-side validation without writing a lot of validation code by adding suitable attributes and also by including the suitable script files.
One of the benefits of using a unobtrusive validation is that it help to reduce the amount of the Java script that is generated. We can install the AspNet.ScriptManager.jQuery? for the unobtrusive validation.
When the unobtrusive validation is used, validation of the client is being performed by using a JavaScript library.
It’s C. An MP3 file is an audio/video file, so only a media player would be able to play this
<span>Not a valid IPv6 address
A valid IPv6 address consist of 8 groups of 4 hexadecimal numbers separated by colons ":". But that can make for a rather long address of 39 characters. So you're allowed to abbreviate an IPv6 address by getting rid of superfluous zeros. The superfluous zeros are leading zeros in each group of 4 digits, but you have to leave at least one digit in each group. The final elimination of 1 or more groups of all zeros is to use a double colon "::" to replace one or more groups of all zeros. But you can only do that once. Otherwise, it results in an ambiguous IP address. For the example of 2001:1d5::30a::1, there are two such omissions, meaning that the address can be any of
2001:1d5:0:30a:0:0:0:1
2001:1d5:0:0:30a:0:0:1
2001:1d5:0:0:0:30a:0:1
And since you can't determine which it is, it's not a valid IP address.</span>
Answer: Between Layers 2 and 3
Explanation:
In between Layer 2 and Layer 3 the MPLS header is present and is known as Shim header. It is also said to be in 2.5.
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
