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andrew11 [14]
3 years ago
15

8 basketball players are to be selected to play in a special game. The players will be selected from a list of 27 players. If th

e players are selected randomly, what is the probability that the 8 tallest players will be selected?
Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer: The probability is unknown

Step-by-step explanation:

The probability of 8 of the tallest players being selected is unknown because there is not a given number of the number of the tallest players

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Which expression is equivalent to 24 Superscript one-third?
Ivahew [28]

Answer:

See explanation

Step-by-step explanation:

The given expression is: (24)^{\frac{1}{3}}

Recall that 24=3*8

\implies(24)^{\frac{1}{3}}=(8*3)^{\frac{1}{3}}

Recall again that:

(a*b)^n=a^n*b^n

\implies (8*3)^{\frac{1}{3}}=(8)^{\frac{1}{3}}*(3)^{\frac{1}{3}}

\implies (8*3)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}*(3)^{\frac{1}{3}}

\implies (8*3)^{\frac{1}{3}}=2^{3*\frac{1}{3}}*(3)^{\frac{1}{3}}

\implies (8*3)^{\frac{1}{3}}=2*(3)^{\frac{1}{3}}

We rewrite in radical form to obtain

\implies (8*3)^{\frac{1}{3}}=2\sqrt[3]{3}

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3 years ago
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Step-by-step explanation:

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3 years ago
Compare and Contrast how you would factor x^2−9 and x^2+9. For full credit, make sure you explain why they are factored differen
marishachu [46]

The factored form of the expression x^2 - 9 is (x+3)(x-3)

The expression x^2 + 9 has no real roots hence cannot be factored

Quadratic equations are equations with a degree of 2.

Given the quadratic function x^2-9 \ and \ x^2+9

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=x^2-9\\=x^2-3^2

Using the difference of two squares:

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For the expression x^2 + 9

The expression x^2 + 9 has no real roots hence cannot be factored

Learn more on factorization here: brainly.com/question/20293447

7 0
2 years ago
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MaRussiya [10]

Answer:

Hello :

(x+4)/(4+x) = (x+4)/(x+4)  = 1   ( answer : C )  but x+4 no : 0



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3 years ago
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