Answer:
Step-by-step explanation:
Given that,
Carlos walk to school on the 14th of 20 days in February.
We need to find the equivalent to the fraction of school days in February that Carlos walk to school.
Required percentage is given by :
or
So, the required fraction is equal to .
Answer:
m<−5
Step-by-step explanation:
Step 1: Flip the equation.
m+4<−1
Step 2: Subtract 4 from both sides.
m+4−4<−1−4
m<−5
Hope this helped <3
Answer:
It's false
Step-by-step explanation:
1.25*200=250 not 300.
Answer:
(a) B
(b) $2
Step-by-step explanation:
(a) Let's say the cost of a ticket is t and the cost of popcorn is p. Then we can write the two equations from the table:
12t + 8p = 184
9t + 6p = 138
We need to solve this, so let's use elimination. Multiply the first equation by 3 and the second equation by 4:
3 * (12t + 8p = 184)
4 * (9t + 6p = 138)
We get:
36t + 24p = 552
36t + 24p = 552
Subtract the second from the first:
36t + 24p = 552
- 36t + 24p = 552
________________
0 = 0
Since we get down to 0 = 0, which is always true, we know that we cannot determine the cost of each ticket because there is more than one solution (infinitely many, actually). The answer is B.
(b) Our equation from this, if we still use t and p, is:
5t + 4p = 82
Now, just choose any of the two equations from above. Let's just pick 9t + 6p = 138. Now, we have the system:
5t + 4p = 82
9t + 6p = 138
To solve, let's use elimination again. Multiply the first equation by 6 and the second one by 4:
6 * (5t + 4p = 82)
4 * (9t + 6p = 138)
We get:
30t + 24p = 492
36t + 24p = 552
Subtract the second from the first:
36t + 24p = 552
- 30t + 24p = 492
________________
6t + 0p = 60
So, t = 60/6 = $10. Plug this back into any of the equations to solve for p:
5t + 4p = 82
5 * 10 + 4p = 82
50 + 4p = 82
4p = 32
p = 32/4 = $8
So the ticket costs 10 - 8 = $2 more dollars than the popcorn.
Answer:
The scale factor is 2.
Step-by-step explanation:
Divide 2 by 1 then you get 2. I got the 2 and the one from the shapes. So don’t get confused ;)
