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3 years ago

In this equation I'm solving for m 12+yu= -zmr

Mathematics

1 answer:

Elenna [48]3 years ago

5 0

$12+yu=-zmr\\\\ \frac{12+yu}{-zr}=m \\\\ \therefore \boxed{m= - \frac{12+yu}{zr} }$

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3 years ago

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Step-by-step explanation:

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3 years ago

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How do I solve part A

seraphim [82]

Answer:

The solution of this expression is $x_{1} = -1$ and $x_{2} = -\frac{1}{2}$ .

Step-by-step explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

$2\cdot x \cdot (x+1.5) = -1$

$2\cdot (x^{2}+1.5\cdot x) = -1$

$2\cdot x^{2} + 3\cdot x = -1$

Step 2:

$2\cdot x^{2}+3\cdot x +1 = 0$

Step 3:

$x_{1, 2} = \frac{-3\pm \sqrt{3^{2}-4\cdot (2)\cdot (1)}}{2\cdot (2)}$

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The solution of this expression is $x_{1} = -1$ and $x_{2} = -\frac{1}{2}$ .

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3 years ago

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3 years ago