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Ksenya-84 [330]
3 years ago
5

What is The midpoint of AB?

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

(-2,0)

Step-by-step explanation:

(-2,0) is the midpoint I believe!

Hope that helps!

frozen [14]3 years ago
4 0

the mid point of AB is 1 and -1

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performance determine the slope and the y-intercept given the following linear functions. 1.f(x)=3x-10​
Monica [59]

Answer:

Slope: 3

Y-Intercept: -10

Step-by-step explanation:

This equation is in slope-intercept form, it is written as y = mx + b where m is the slope and b is the y-intercept. This means 3 is the slope and -10 is the y-intercept.

3 0
3 years ago
Solve 8x2 - 7 = 193.
Gelneren [198K]

Answer:

Hi, there the answer is B. Trust me

Step-by-step explanation:

6 0
3 years ago
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please only answer if you're a hundred percent sure you know the correct answer and please answer all question
Alika [10]

Answer:

Q.no.1

d=1 then t=7

d=3 then t=11

t=15 then d=5

Q.no.2

d=1 then t=3

d=3 then t=9

t=15 then d=5

Q.no.3

5x = 12+18

or, 5x = 30

or, x =30/5

or, x = 6

Q.no.6

x < 8

Q.no.7

x >_ 7 ( option d)

Hope it helps.

8 0
3 years ago
the total cost of a pizza and 3 drinks is $19 the price of the pizza is $10 and each drink is the same price D what is the price
mixas84 [53]

Answer:

3

Step-by-step explanation:

9 divide by 3 is 3 itself so the answer is 3

3 0
3 years ago
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Show that Circle R with center (2, -9) and radius 5 is similar to Circle Q with center (-4, 3) and radius 3 by using a series of
faltersainse [42]

Answer:

It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).

Step-by-step explanation:

We can demonstrate that Circle R is similar to Circle Q by translating the center of the former one to the center of latter one. Meaning that every point of circle R experiments the same translation. Vectorially speaking, a translation is defined by:

O'(x,y) = O(x,y) + T(x,y) (1)

Where:

O(x,y) - Original point.

O'(x,y) - Translated point.

T(x,y) - Translation vector.

If we know that O(x,y) = (2,-9) and O'(x,y) = (-4,3), then the translation vector is:

T(x,y) = O'(x,y)-O(x,y)

T(x,y) = (-4,3) - (2,-9)

T(x,y) = (-6,12)

It can be proved that the circle R is similar to the circle Q by translating the circle R a displacement of (-6, 12).

4 0
3 years ago
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