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olga nikolaevna [1]
3 years ago
15

The gravitational pull of the Moon has the greatest influence on the water levels of Earth’s ocean tides. If the distance betwee

n the Moon and Earth were to decrease steadily for one week, which water-level changes would be expected to occur?
Chemistry
1 answer:
kherson [118]3 years ago
6 0
The water levels would lower, because as the moon gets farther away, it's gravitational pull decreases. Hope this helps! :)
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How is atomic number different from mass number?
Nimfa-mama [501]
Hello Gary My Man!

Well, as you can clearly see 

<span>The atomic number of an element is basically the number of protons it has. So yes, for every element this is different. Now, the mass number of an element as known, is the number of protons+the number of neutrons.  So theoretically as we can see, this number should be a whole number, but since there are different isotopes (atoms of the same element with different numbers of neutrons) of each element, most periodic tables take account of that, so they often include decimals as seen. 

So in Short, ALL</span> the atoms of a particular element have the SAME EXACT atomic number<span> (</span>number<span> of protons of course). The </span>atoms of different elements have very different numbers of protons. And of course, the MASS number of an atom is the TOTAL number as known, of protons and of course, the neutrons it contains in it.

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

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7 0
3 years ago
Draw a molecular model of sulfur trioxide.
bija089 [108]

Answer:

Here's what I get  

Explanation:

The Lewis structure of SO₃ consists of a central sulfur atom double-bonded to each of three oxygen atoms that points to the corners of an equilateral triangle.

A ball-and-stick model of SO₃ is shown below.

6 0
3 years ago
What is the charge associated with each side of the HCl molecule?
Alexandra [31]

HCl is a polar molecule with the hydrogen part being partial positive while the chlorine end being partial negative. This is because hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. This means that chlorine attracted most of the electron cloud of molecule hence is the negative dipole, The dipole moment of HCl is 1.08 D (debyes). A Debye is equal to 3.34 x 10-30 coulomb-meters (C-m). The charge of each molecule is o.176+ for H and 0.176- for the Cl

3 0
3 years ago
Read 2 more answers
g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc
Gala2k [10]

\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}

\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}

\text{and in the liquid form it is easily transported. An industrial chemist studying this}

\text{reaction fills a} \ \mathbf{100 \  L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \  \text{of oxygen gas, }

\text{to be} \  \mathbf{2.6\  mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}

\text{ammonia at the final temperature of the mixture. Round your answer to  2 significant digits.}

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

From the above reaction; the ICE table can be represented as:

                    \mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }

I (mol/L)     0.086            0.28                 0              0

C                   -4x                -3x               +2x           +6x

E                 0.086 - 4x     0.28 - 3x      +2x             +6x

At equilibrium;

The water vapor = \dfrac{2.6 \ mol}{100 \ L} = 6x

x = \dfrac{2.6}{100} \times \dfrac{1}{6}

x = 0.00433

\text{equilibrium constant}  ({k_c}) =  \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }

\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\

Replacing the value of x, we have:

K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}

K_c = \mathbf{5.5 \times 10^{-8} \ to  \ 2 \ significant \ figures}

5 0
3 years ago
A sample of helium gas has a volume of 620. Ml at a temp of 500 K. If we decrease the temperature to 100K while keeping the pres
Ne4ueva [31]

Answer:

A sample of helium gas has a volume of 620mL at a temperature of 500 K. If we ... to 100 K while keeping the pressure constant, what will the new volume be?

Explanation:

3 0
3 years ago
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