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Alik [6]
4 years ago
12

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

gh if its z score is greater than or equal to 2.
A test is used to assess readiness for college. In a recent​ year, the mean score was 22.5 and the standard deviation was 5.1. Identify the scores that are significantly low or significantly high.
Mathematics
1 answer:
Kisachek [45]4 years ago
3 0
The z-score is given by:
z-score=(x-μ)/σ
where:
x=score
μ=mean=22.5
σ=std deviation=5.1
given that the z-score is -2, then the lowest cost will be:
-2=(x-22.5)/5.1
solving for x we get:
-10.2=x-22.5
x=-10.2+22.5
x=12.3
therefor the lowest score is 12.3

Given that the z-score is 2 when the score is highest, then highest score will be:
2=(x-22.5)/5.1
10.2=x-22.5
x=10.2+22.5
x=32.7
therefore the highest score is 32.7
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<h3>Answer:  24 minutes</h3>

===================================================

Explanation:

Let's say the lawn is 120 square feet. I picked 120 as it is the LCM (lowest common multiple) of 60 and 40.

Since Wilma can mow the lawn in 60 minutes, her rate is 120/60 = 2 sq ft per minute. In other words, each minute means she gets 2 more square feet mowed. Rocky can do the full job on his own in 40 minutes, so his rate is 120/40 = 3 sq ft per minute.

Their combined rate, if they worked together (without slowing each other down), would be the sum of the two rates. So we get 2+3 = 5 sq ft per minute as the combined rate. The total time it would take for this 120 sq ft lawn is 120/5 = 24 minutes.

--------------------------

Another approach

Wilma takes 60 minutes to do the full job, so her rate is 1/60 of a lawn per minute. Rocky's rate is 1/40 of a lawn per minute. Their combined rate is

1/60 + 1/40 = 2/120 + 3/120 = 5/120 = 1/24 of a lawn per minute

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(combined rate)*(time) = number of jobs done

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The equation above is equivalent to C*(1/A + 1/B) = 1 or (1/A + 1/B)*C = 1.

So basically you find the value of 1/A + 1/B, then find the reciprocal of this to get the value of C.

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