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Trava [24]
3 years ago
11

Watch the animation depicting Rutherford's experiment and choose which of the following conclusions are correct.Check all that a

pply.1. The mass of an atom is concentrated at the nucleus.2. A positive charge is spread equally over the atom.3. Positive charge is condensed in one location within the atom.4. The majority of the space inside the atom is empty space.5. The atom is a very compact entity without any empty space.6. The atom contains a positively charged nucleus.
Chemistry
1 answer:
Blababa [14]3 years ago
6 0

Answer:

  • <em>1. The mass of an atom is concentrated at the nucleus.</em>

<em />

  • <em>3. Positive charge is condensed in one location within the atom.</em>

<em />

  • <em>4. The majority of the space inside the atom is empty space.</em>

<em />

  • <em>6. The atom contains a positively charged nucleus.</em>

Explanation:

When J.J Thmpson discovered the electron, he depicted the atom by the plum pudding model: a solid dough of homogeneously distributed positive charge (the pudding) containing negatively charged electrons (the plums).

Later, the scientist <em>Ernest Rutherford</em>, with its experiment of the gold foil experiment showed that the subatomic particles where not all concentrated in a solid part.

When a thin gold foil was bombarded with alpha particles (positively charged nuclei of helium atoms), most of the particles went through the gold sheet, with little deviation, but some particles bounded with a high deviation.

Such few high deviations were explained by the fact that there was a heavy region in the atom (the core or nucleus) with the positive charge that repelled the positively charged alpha particles.

Thus, <em>the mass of the atom was conentrated at the nucleus</em> (choice 1), where the positive charge is distributed in one location, which is the nucleus (not over the entire atom, just on the nucleus) discarding the choice number 2 (that a positive charge is spread equally over the atom) and proving choices 3 (<em>the positive charge is condensed in one location within the atom</em>) and 6 (<em>the atom contains a positively charged nucleus</em>).

Since most of the particles indeed went through the nucleus, this nucleus has to  occupy little space, and most of the atom was empty space, proving choice 4 (<em>the majority of the space inside the atom is empty space</em>).

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2mL of a serum sample was added to 18mL of phosphate buffered saline (PBS) in Tube 1. 10mL of Tube 1 was added to 40mL of PBS in
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Answer:

Tube 2 has a total dilution of 1:50

Explanation:

We have a 2 ml serum sample added to a 18 mL phosphate buffered saline sample in tube 1. This means now in tube 1 there is 20 mL.

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10 ml of this 1:10 diluted tube 1 is taken and added to a 40 mL of PBS in tube 2.

Now we have 50 mL in tube 2.

This is a 10:50 (= 1:5) dilution.

The total dilution is 10x5 = 50

So the total ditultion has a rate 1:50

Tube 2 has a total dilution of 1:50

4 0
3 years ago
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almond37 [142]
Air has mass and density, and. cold air is denser than warm air.
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7 0
2 years ago
Which statements describe Rutherford’s model of the atom? Select three options.
AnnZ [28]

Answer:

Well, I cannot see the options but if I were you I would choose the one closest to this. Rutherford's model shows that an atom is mostly empty space, with electrons orbiting a fixed, positively charged nucleus in set, predictable paths.

Explanation:

Again I cannot see the options but here is what I would guess. Hope this helped and have a great day! :-)

6 0
2 years ago
Read 2 more answers
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Answer:

See explanation below

Explanation:

You forgot to put the picture to do so. In this case, I manage to find one, and I hope is the one you are looking for. If not, then post it again and I'll gladly help you out again.

According to the picture with the answer, we have a cyclohexane with 4 methyl groups there. Two of them are facing towards the molecule with a darker bond. This means that the alkyl bromide, should have a bromine in one of the bonds, and in order to produce an E2 reaction, this bromine should be facing in the opposite direction of the methyl groups which are facing towards. This is because an E2 reaction occurs with the less steric hindrance in the molecule. If the bromine is in the same direction as the methyl group, it will cause a lot more of work to do a reaction, and therefore, an E2 reaction. I will promote instead a E1 or a sustitution product.

Therefore the alkyl bromide should be like the one in the picture 2.

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3 years ago
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kykrilka [37]
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To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.
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