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Trava [24]
4 years ago
11

Watch the animation depicting Rutherford's experiment and choose which of the following conclusions are correct.Check all that a

pply.1. The mass of an atom is concentrated at the nucleus.2. A positive charge is spread equally over the atom.3. Positive charge is condensed in one location within the atom.4. The majority of the space inside the atom is empty space.5. The atom is a very compact entity without any empty space.6. The atom contains a positively charged nucleus.
Chemistry
1 answer:
Blababa [14]4 years ago
6 0

Answer:

  • <em>1. The mass of an atom is concentrated at the nucleus.</em>

<em />

  • <em>3. Positive charge is condensed in one location within the atom.</em>

<em />

  • <em>4. The majority of the space inside the atom is empty space.</em>

<em />

  • <em>6. The atom contains a positively charged nucleus.</em>

Explanation:

When J.J Thmpson discovered the electron, he depicted the atom by the plum pudding model: a solid dough of homogeneously distributed positive charge (the pudding) containing negatively charged electrons (the plums).

Later, the scientist <em>Ernest Rutherford</em>, with its experiment of the gold foil experiment showed that the subatomic particles where not all concentrated in a solid part.

When a thin gold foil was bombarded with alpha particles (positively charged nuclei of helium atoms), most of the particles went through the gold sheet, with little deviation, but some particles bounded with a high deviation.

Such few high deviations were explained by the fact that there was a heavy region in the atom (the core or nucleus) with the positive charge that repelled the positively charged alpha particles.

Thus, <em>the mass of the atom was conentrated at the nucleus</em> (choice 1), where the positive charge is distributed in one location, which is the nucleus (not over the entire atom, just on the nucleus) discarding the choice number 2 (that a positive charge is spread equally over the atom) and proving choices 3 (<em>the positive charge is condensed in one location within the atom</em>) and 6 (<em>the atom contains a positively charged nucleus</em>).

Since most of the particles indeed went through the nucleus, this nucleus has to  occupy little space, and most of the atom was empty space, proving choice 4 (<em>the majority of the space inside the atom is empty space</em>).

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the answer is O²- hopefully

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3 years ago
a compound is composed of only c h and O. Combustion of a 519 gram sample of the compound yields 1.24 grams of CO2 and?
densk [106]

Answer:

C3H3O

Explanation:

Question incomplete needs to be rewritten:

A compound is composed of only C, H, and O. The combustion of a .519-g sample of the compound yields 1.24g of CO_2 and 0.255 g of H_2 O. What is the empirical formula of the compound

We can get the answer through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 1.24/44= 0.0282

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above

The mass of carbon in the compound is simply the number of moles multiplied by the atomic mass unit. The atomic mass unit of carbon is 12. The mass of carbon in the compound is thus 12 * 0.0282= 0.338

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.255/18= 0.0142 moles

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.0142= 0.0283

The mass of hydrogen is thus 0.0283 * 1 = 0.0283g

The mass of oxygen equals the mass of the compound minus that of hydrogen and that of carbon.

= 0.519 - 0.338 - 0.0283= 0.1527g

The number of moles of oxygen is the mass of oxygen divided by its atomic mass unit.

That equals 0.1527/16= 0.00954375 moles

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that oxygen 0.00954375 moles

H = 0.0284/0.00954375 = 2.97 = 3

O = 0.00954375/0.00954375= 1

C = 0.0282/0.00954375 = 2.95 = 3

The empirical formula is thus C3H3O

7 0
4 years ago
4.
Mila [183]

Answer:

0.47m²

Explanation:

Given parameters:

Length = 9.025 x 10⁶m

Width  = 5.215 x 10⁻⁸m

Unknown:

Area of the rectangle  = ?

Solution:

Area is the derived from the product of the length and width of a body.

 Area  = length x width  = 9.025 x 10⁶m  x  5.215 x 10⁻⁸m

  Area  = 0.47m²

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3 years ago
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Answer:6

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4 years ago
A process or reaction which takes in heat from the surroundings is said to be
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