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3 years ago

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A homogeneous mixture is also called _______________. a solution. an element. a pure substance. a heterogeneous mixture. a compo

und.

1 answer:

inessss [21]3 years ago

6 0

A solution is right answer.

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The ________ ion is represented by the electron configuration [ar]3d2.

Tresset [83]

The Ti 2+ ions is represented by electron configuration (Ar)3d2. Titanium is in atomic number 22 and its electronic configuration is (Ar)3d2 4s2. Titanium loss two electron that is 4s2 electrons hence the electronic configuration ( Ar)3d2. 4s2 is the valence electron hence it the one which is lost to form Ti2+

3 0

3 years ago

Read 2 more answers

Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).

12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by $\Delta T$ is given by the equation:

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

$C=0.385 J/gK$ is the specific heat capacity of copper

$\Delta T=400-300 = 100 K$ is the change in temperature

So, the energy absorbed by the block of copper is

$Q=(10)(0.385)(100)=385 J$

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

$Q=mC\Delta T$

where

m is the mass of the block of iron

C is its specific heat capacity of iron

$\Delta T$ is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

$C=0.450 J/gK$ is the specific heat capacity of iron

$\Delta T=400-300 = 100 K$ is the change in temperature

So, the energy absorbed by the block of iron is

$Q=(10)(0.450)(100)=450 J$

6 0

2 years ago

The average lung capacity of a human is 6.0L.

Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol$

(b)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol$

(c)

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

n = number of moles = ?

Putting values in above equation, we get:

$30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol$

8 0

3 years ago

The temperature

solniwko [45]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\texttt {The reaction releases energy}$ $\texttt{( - or Exothermic)}$

____________________________________

$\large \tt Explanation \: :$

Temperature of thermometer increases during the reaction, that means it receives heat. henceforth we can conclude that energy is released during the reaction that cleary mean that it's an Exothermic Reaction.

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

Nitrogen gas exerts a pressure of 846mmhg. When the pressure is changed to 2.5atm its volume is 63.9l. What was the original vol

Aloiza [94]

Explanation:

$760 \: mmHg \: = \: 1 \: atm \\ 846 \: mmHg \: = \: ( \frac{846}{760} ) \: atm \\ = 1.1 \: atm \\ \\ P _{1} V _{1} = P _{2}V _{2} \\ 1.1 \times V _{1} = 2.5 \times 63.9 \\ V _{1} = \frac{2.5 \times 63.9}{1.1} \\ V _{1} = 145.2 \: litres$

3 0

3 years ago