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3 years ago

Which of the following chemical formulas would require a prefix when named?

Chemistry

2 answers:

Tanzania [10]3 years ago

7 0

The following chemical formulas would require a prefix when is it named, Cl207

Vlad [161]3 years ago

3 0

The answer would be CI207! :D

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Scientists excavating at the bottom of the ocean come across fossilized remains of an ancestor of a mountain goat. How can this

galina1969 [7]

There was land on that surface before there was water

4 0

3 years ago

The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 2.001 g sample of B

Alborosie

Answer: The empirical formula for the given compound is $C_{15}H_{24}O_1$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=5.995g$

Mass of $H_2O=1.963g$

Mass of sample = 2.001 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 5.995 g of carbon dioxide, $\frac{12}{44}\times 5.995=1.635g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.963 g of water, $\frac{2}{18}\times 1.963=0.218g$ of hydrogen will be contained.

Mass of oxygen in the compound = (2.001) - (1.635 + 0.218) = 0.148 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.635g}{12g/mole}=0.136moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.218g}{1g/mole}=0.218moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.148g}{16g/mole}=0.0092moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0092 moles.

For Carbon = $\frac{0.136}{0.0092}=14.78\approx 15$

For Hydrogen = $\frac{0.218}{0.0092}=23.69\approx 24$

For Oxygen = $\frac{0.0092}{0.0092}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 15 : 24 : 1

Hence, the empirical formula for the given compound is $C_{15}H_{24}O_1$

3 0

4 years ago

The reaction 2a + b --> c + d has an activation energy of 80.0 kj/mol. at 320°c, the rate constant k = 1.80 x 10-2 l mol-1 s-

Naddik [55]

To determine the k for the second condition, we use the Arrhenius equation which relates the rates of reaction at different temperatures. We do as follows:

ln k1/k2 = E / R (1/T2 - 1/T1) where E is the activation energy and R universal gas constant.

ln 1.80x10^-2 / k2 = 80000 / 8.314 ( 1/723.15 - 1/593.15)

k2 = 0.3325 L / mol-s

5 0

4 years ago

Determine the freezing point of 0.368 kg of H2O with 11.85 g of C2H5OH where the kf is 1.86 C/m.

saveliy_v [14]

We will use the formula for freezing point depression :

but first, we need to get the molality m of the solution:

- molality m = moles of C2H5OH / mass of water Kg

when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH

= 11.85 g / 46 g/mol

= 0.258 moles

and when we have the mass of water Kg = 0.368 Kg

so, by substitution on the molality formula:

∴ molality m = 0.258 moles / 0.368 Kg

= 0.7 mol/Kg

and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1

and when Kf is given = 1.86 C/m

so by substitution on ΔTf formula:

when ΔTf = i Kf m

∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg

= 1.302 °C

5 0

3 years ago

What happens when you heat an air filled sealed can ?

Mandarinka [93]

The pressure increases and would explode

8 0

3 years ago