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Varvara68 [4.7K]
3 years ago
10

The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and

how many adults attended.
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

Answer:

1200 children and 1500 Adults

Step-by-step explanation:

Suppose x be the children and y be the adults as total people are 2700 that have entered so we can write an equation as  

x+y=2700    (Equation 1)

and as per child $1.50 is the cost and $4 for every adult and collectively we have got $7800 so we can write the equation as  

1.50x+4y=7800 (Equation 2)

Extracting the value of y from equation 1

Y=2700-x (Equation 3)

Putting the value of y from equation 3 into equation 2

1.50x+4(2700-x)=7800

1.50x+10800-4x=7800

1.50x-4x=7800-10800

-2.5x=-3000

Cancellation of negative signs on both sides

x=3000/2.5

x=1200

Putting the value of x in equation 3 to get the value of y

y=2700-1200

y=1500

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At high school basketball game, the athletic department sold 250 tickets and brought in 837.50. Adult tickets cost $5 and studen
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Answer:

The system of equations is:

a+s = 250\\5a+2.50s = 837.50

Here a is the number of adult tickets and s is the number of student tickets

Step-by-step explanation:

We will use the given statements to make a system of equations for the given scenario.

First of all we have to decide which variables to be used.

Let a be the number of adult tickets and

Let s be the number of student tickets

So according to the statement that the department sold 250 tickets in total, the equation will be:

a+s = 250

This is equation one of the system of equations

According to the statement that cost of adult ticket is $5, total cost of adult tickets will be: 5a

According to the statement that cost of student ticket is $2.50, total cost of student tickets will be:2.50s

The total earning was $837.50 so the second equation will be:

5a+2.50s = 837.50

Hence,

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