When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.
If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.
Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so .
Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so .
Subtract from the first equation the second equation:.
Similarly you can prove that .
Solve the system of inequalities by graphing. y< – 5 y≤ – 6x–3
1 answer:
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Answer:
Step-by-step explanation:
We'll use rule of exponents to simplify expression.
Now, use the commutative property of multiplication.
In order to multiply power of the same base, we add their exponents.
→ Add exponents:
→ Multiply 3* -8
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