Answer:
23 degrees
Step-by-step explanation:
First, subtract 9 from 29 to find the temperature at 9 A.M. The temperature at 9 A.M. was 20 degrees. The temperature from 5 A.M. doubled to get to the temperature at 9 A.M., so divide 20 by 2. The temperature at 5 A.M. was 10 degrees. The temperature from midnight to 5 A.M. fell 13 degrees, so add 13 to get the temperature at midnight. 13+10=23. It was 23 degrees at midnight.
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=

we got
a=1
b=6
c=-50
W=

W=

W=

W=

W=

W=

or W=

aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
Answer:
B
Step-by-step explanation:
<u>This is a right triangle as shown by the right angle.</u>
- The side opposite the right angle is the hypotenuse, which is 9.
- The side opposite angle A is 3.
So we have the opposite of A and the hypotenuse.
The trigonometric ratio that relates opposite side to hypotenuse is SINE.

Since, we need angle A,
is A, opposite side is 3, and hypotenuse is 9, we substitute:

<em>To solve for the angle, we use our calculator and find the inverse sin of
:</em>

<em>Rounding to nearest tenth of a degree:</em>

B is the right choice.
The slope-intercept form:

m - slope
b - y-intercept
The formula of a slope:

We have two points (2, 0) and (-2, -4). Substitute:

Therefore we have the equation of a line

Put the coordinates of the point (2, 0) to the equation:
<em>subtract 2 from both sides</em>

Answer: 
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>