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klemol [59]
2 years ago
12

A ticket to see your favorite baseball team costs ​$30.08. That price decreases by ​$0.42 for every game lost during the regular

season. What equation could you use to find the cost C of a ticket after L​ losses? Represent the total change in the cost of a ticket after the team loses 27 games. What is the price of a ticket after the team loses 27 ​games?
Mathematics
1 answer:
allsm [11]2 years ago
3 0

Given :

A ticket to see your favorite baseball team costs ​$30.08.

That price decreases by ​$0.42 for every game lost during the regular season.

To Find :

What equation could you use to find the cost C of a ticket after L​ losses.

Solution :

Let, n is number of match loses and P is the price of ticket.

So, equation is given by :

P = 30.08 - (0.42)n           .......1)

Putting n = 27 in above equation,we get :

P = 30.08 - ( 0.42 )( 27 )

P = $18.74

Therefore, the price of a ticket after the team loses 27 ​games is $18.74 .

Hence, this is the required solution.

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vaieri [72.5K]

Answer:

23 degrees

Step-by-step explanation:

First, subtract 9 from 29 to find the temperature at 9 A.M. The temperature at 9 A.M. was 20 degrees. The temperature from 5 A.M. doubled to get to the temperature at 9 A.M., so divide 20 by 2. The temperature at 5 A.M. was 10 degrees. The temperature from midnight to 5 A.M. fell 13 degrees, so add 13 to get the temperature at midnight. 13+10=23. It was 23 degrees at midnight.

8 0
2 years ago
the length of a rectangle is 6in.more than than its width .Its area is 50 sq.in Find the width of the rectangle....
yulyashka [42]
L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
we got
a=1
b=6
c=-50


W=\frac{-(6)+/- \sqrt{(6)^2-4(1)(-50)} }{2(1)}
W=\frac{-6+/- \sqrt{36+200} }{2}
W=\frac{-6+/- \sqrt{236} }{2}
W=\frac{-6+/- 2\sqrt{59} }{2}
W=-3+/- \sqrt{59}

W=-3+ \sqrt{59} or W=-3- \sqrt{59}
aprox
W=-10.6811 or W=4.68115
can't be negative width

width=4.68115 or -3√59
7 0
3 years ago
The measure of angle A to the nearest tenth of a degree is: A 18.5 B 19.5 C 20.5
Andrew [12]

Answer:

B


Step-by-step explanation:

<u>This is a right triangle as shown by the right angle.</u>

  • The side opposite the right angle is the hypotenuse, which is 9.
  • The side opposite angle A is 3.

So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

sin\theta=\frac{opposite}{hypotenuse}

Since, we need angle A, \theta is A, opposite side is 3, and hypotenuse is 9, we substitute:

sinA=\frac{3}{9}\\sinA=\frac{1}{3}

<em>To solve for the angle, we use our calculator and find the inverse sin of \frac{1}{3} :</em>

A=sin^{-1}(\frac{1}{3})\\A=19.47

<em>Rounding to nearest tenth of a degree:</em>

A=19.5

B is the right choice.

6 0
3 years ago
What is the equation of the line in the following graph? 1)y=x+2
Levart [38]

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (2, 0) and (-2, -4). Substitute:

m=\dfrac{-4-0}{-2-2}=\dfrac{-4}{-4}=1

Therefore we have the equation of a line

y=1x+b\to y=x+b

Put the coordinates of the point (2, 0) to the equation:

0=2+b     <em>subtract 2 from both sides</em>

-2=b\to b=-2

Answer: \boxed{y=x-2}\to\boxed{3)}

8 0
3 years ago
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Allisa [31]

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For line A to BC:  y - 6 = (-1)(x - 0);  y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

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<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>

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